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2 years ago

At first, Kai earned a score of 80 on a quiz. He discovered that 5 points had been taken

Mathematics

2 answers:

DedPeter [7]2 years ago

8 0

Answer:

The two expressiones that could be uses to find Kai's new quiz score are:

1. 80 + 5

2. 80 - ( -5 )

Step-by-step explanation:

The initial score in the Kai quiz was 80, but when the professor noticed his mistake, he raised the 5 points that he had subtracted by mistake.

80 + 5; It shows that the professor corrected the negative points that Kai had in his Quiz.

80 - (-5); By subtracting a negative amount, what is done is to transform the negative number into a positive number and add it. 80 - (-5) = 80 +5 = 85

mario62 [17]2 years ago

5 0

Initial score was 80. There was an accidental 5 point deduction. This means anything that gives 85 is the correct answer.

80 + 5 = 85

80 - (-5) = 85

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Jesse has a storage container in the shape of a right rectangular prism. The volume of the container is 43.875 cubic meters, the

AVprozaik [17]

All you have to do is divide the volume of the container (43.875) by 5 (length) and 3.9 (width) because the formula for the volume of a rectangular prism is V=lwh. So the answer/height of the storage container is 2.25 meters

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2 years ago

Read 2 more answers

A six-sided fair die is rolled and a fair coin is tossed. If event M represents getting an odd number on the die and event N rep

poizon [28]

Answer:

The two events are independent. In the given scenario, P(M and N) =0.25

Explanation:

1) Independent events are those that do not affect each other. In this case the number that you roll does not change the flip of the coin. So, whatever number you get with the die, the probabilities of landing tail or head when tossing the coin are the same.

2) The probability of the two simultaneous events: getting an odd number and landing a tail, since they are independent, is equal to the product of the two independent events:
P(M and N) = P(M) x P (N) (only because they are independent)

3) The probability of getting and odd number is 0.5 (half of the numbers are odd and half are even => probability = 1/2)

4) The probability of the coin lands tail is 0.5 (1/2).

5) Then the joint probability is 0.5 x 0.5 = 0.25

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2 years ago

Given a 10 foot length of tree trunk with a radius of 3 feet, what is the weight of the tree trunk section if it has a density o

Soloha48 [4]

You will use the formula for the mass of a cylinder. Since the trunk forms like a cylinder.

It is Mcylinder = density x pi x radius x height

So the given in our problem is:

Density = 45 lb/ft^3

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Height = 10 ft

Plugging that in our equation:

M cylinder = 45 lb/ft^3 * pi * 3ft^2 * 10 ft

= 5771.26 kgs

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2 years ago

The class president collected data on 150 randomly selected 17-year-olds at his school. He surveyed students on if they had a jo

telo118 [61]

Answer:

Step-by-step explanation:

Part A can be seen in the attached picture below. Since there are 76 students that have both a license and a job we need to subtract 76 from each to get the amount that only have either a license or a job as seen in the table. Also we can see from the table that it sums up to 145 students, meaning that 5 students do not have neither a job or a license.

Part B, to calculate this we need to divide the amount of students that ONLY have a job by the total amount of students that have a job (since the rest of those students also have a license) Therefore:

17 / 93 = 0.1828

Now we can multiply this result by 100 to get the percentage.

0.1828 * 100 = 18.28%

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2 years ago

Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road-oriented at an angle of 25

kap26 [50]

Answer:

6.31 mi

Step-by-step explanation:

The diagram below explains the solution better.

From the diagram,

C = starting point of the race.

A = end of the first part of the race.

B = end of the race.

Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.

Cosine rule states that:

$a^2 = b^2 + c^2 - 2bc[cos(A)]$

where A = angle A = <A

Given that

b = 5.2 miles

c = 2.0 miles

<A = 115° (from the diagram)

Hence,

$a^2 = 5.2^2 + 2.0^2 - 2*5.2*2.0[cos(115)]\\\\a^2 = 27.04 + 4 - 20.8[cos(115)]\\\\a^2 = 31.04 + 8.79\\\\a^2 = 39.83\\\\a = \sqrt{39.83}\\ \\a = 6.31 mi$

The straight-line distance between the starting point and the end of the race is 6.31 mi

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2 years ago