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nexus9112 [7]
2 years ago
3

A game has a rectangular board with an area of 44in2. There is a square hole near the top of the game board in which you must no

t toss in a bean bag. The square has side lengths of 3in. What is the probability of tossing the bag through the hole?
Mathematics
2 answers:
enyata [817]2 years ago
5 0

Answer:  The required probability is 20.45%.

Step-by-step explanation:  Given that a game has a rectangular board with an area of 44 in² and a square hole near the top of the game board in which we must not toss in a bean bag. The square has side lengths of 3 in.

We are to calculate the probability of tossing the bag through the hole.

The area of the rectangular board, A = 44 in²

and

the area of the square hole, a = 3 × 3 = 9 in².

Therefore, the probability of tossing the bag through the hole is given by

P=\dfrac{a}{A}=\dfrac{9}{44}=0.2045=20.45\%.

Thus, the required probability is 20.45%.

boyakko [2]2 years ago
4 0
The area of the hole would be 9 in^2 if it is considered that every space withing the board has equal possibilities then 

9/44 = 0.204 = 20.4% 

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iren [92.7K]

Answer:

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2.  (x-4)(y+7)

Step-by-step explanation:

1a)

The length given as words is "3 more than 7 times x"

The width given as words is "4 times x minus 2"

The expression for length would be  7x + 3

The expression for width would be 4x - 2

1b)

The area is length * width

Since we already know the algebraic expressions for length and width from part (a) above, we use the formula:

Area = (7x+3)(4x-2) = 28x^2 -14x + 12x - 6 = 28x^2 -2x -6

Area = 28x^2 -2x -6

1c)

Given x = 10, we put this into the area expression we found in (b) above.Let's see:

28x^2 -2x -6\\=28(10)^2 -2(10) -6\\=2774

Area = 2774 sq. m

2.

We can group the first two terms and next two terms and write up:

xy-4y+7x-28\\(xy-4y)+(7x-28)\\y(x-4)+7(x-4)\\(x-4)(y+7)

That's the factored form.

8 0
2 years ago
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A poll found that 64% of a random sample of 1076 adults said they believe in ghosts.
Dennis_Churaev [7]

Answer:

Margin of error at 90% is 0.024

Margin of error at 99% is 0.037

Step-by-step explanation:

Sample size = 1076

A poll found that 64% of a random sample of 1076 adults said they believe in ghosts.

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\widehat{p} = \frac{x}{n}

\widehat{p} = \frac{688}{1076}

\widehat{p} = 0.639

ME=z \times \sqrt{\frac{\widehat{p}(1-\widehat{p})}{n}}

z at 90% confidence is 1.64

ME=1.64 \times \sqrt{\frac{0.639(1-0.639)}{1076}}

ME=0.024

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z at 99% confidence is 2.58

ME=2.58 \times \sqrt{\frac{0.639(1-0.639)}{1076}}

ME=0.024

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2 years ago
Based on the graph shown to the right, whose phones cost varies directly with the amount of time spent talking?
Lena [83]

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Nutka1998 [239]
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pentagon [3]

Answer:

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_____

<em>Comment on this measurement</em>

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