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Nswer two questions about Systems A AA and B BB: System A AA start text, end text System B BB { − 3 x + 12 y = 15 7 x − 10 y = −

rjkz [21]

Answer:

(Choice C) C Replace one equation with a multiple of itself

Step-by-step explanation:

Since system A has the equations

-3x + 12y = 15 and 7x - 10y = -2 and,

system B has the equations

-x + 4y = 5 and 7x - 10 y = -2.

To get system B from system A, we notice that equation -x + 4y = 5 is a multiple of -3x + 12y = 15 ⇒ 3(-x + 4y = 5) = (-3x + 12y = 15).

So, (-x + 4y = 5) = (1/3) × (-3x + 12y = 15)

So, we replace the first equation in system B by 1/3 the first equation in system A to obtain the first equation in system B.

So, choice C is the answer.

We replace one equation with a multiple of itself.

7 0

2 years ago

On a coordinate plane, parallelogram P Q R S is shown. Point P is at (negative 2, 5), point Q is at (2, 1), point R is at (1, ne

Oksanka [162]

Answer:

The perimeter is $(8\sqrt{2}+2\sqrt{10})\ units$

Step-by-step explanation:

we know that

A parallelogram is a quadrilateral where both pairs of opposite sides are parallel and equal

so

In this problem

PS=QR ----> equation A

SR=PQ ----> equation B

The perimeter of parallelogram PQRS is

P=PQ+QR+SR+PS ----> equation C

substitute equation A and equation B in equation C

$P=2SR+2QR$

we have

$QR=\sqrt{10}\ units$

$SR=4\sqrt{2}\ units$

substitute in the formula of perimeter

$P=2(4\sqrt{2})+2(\sqrt{10})$

$P=(8\sqrt{2}+2\sqrt{10})\ units$

7 0

2 years ago

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N(17+x)=34x−r<br> I need to solve for x

Paraphin [41]

Answer:

The value of x is, $x= \frac{17N+r}{34-N}$

Explanation:

Given: $N(17+x)=34x-r$

Distributive Property states that when a number is multiplied by the sum of two numbers, the first number can be distributed to both of those numbers and multiplied by each of them separately.

If $a\cdot(b+c) =a\cdot b + a\cdot c$

Now, using distributive property on left hand side of the given expression as:

$N\cdot 17+N\cdot x = 34x-r$ or $17N+Nx = 34x-r$

Addition Property of equality state that we add the same number from both sides of an equation.

Add r to both sides of an equation:

$17N+Nx+r=34x-r+r$

Simplify:

$17N+Nx+r=34x$

Subtraction Property of equality state that we subtract the same number from both sides of an equation.

Subtract Nx from both sides of an equation;

$17N+Nx+r-Nx=34x-Nx$

Simplify:

$17N+r=34x-Nx$

or

$17N+r=x(34-N)$

Division Property of equality states that we divide the same number from both sides of an equation.

Divide by (34-N) to both sides of an equation;

$\frac{17N+r}{34-N}= \frac{x(34-N)}{34-N}$

On Simplify:

$x= \frac{17N+r}{34-N}$

4 0

2 years ago

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The table below represents the closing prices of stock ABC for the last five

Ilia_Sergeevich [38]

Answer:

b

Step-by-step explanation:

just trust me

7 0

1 year ago

A turtle and a rabbit engage in a footrace over a distance of 4.00 km. The rabbit runs 0.500 km and then stops for a 90.0-min na

Oxana [17]

Answer:

(a) 2.29 km/h

(b) 9 km/h

Step-by-step explanation:

For part (a) you have to apply<em> the average speed formula</em>, which is defined by:

$v=\frac{d}{t}$

where d is the total distance traveled and t is the total time needed.

$d=\frac{4.00}{1.75}=2.29$ km/h

For part (b) you have to calculate the running time (T) , which is the total time of the race minus the nap time:

The nap time in hours is:

90/60 = 1.5 h (because there are 60 minutes in one hour)

The running time is:

T= 1.75 - 1.5 = 0.25 h

Let t1 represent the time before the nap and t2 the time after the nap:

t1+t2 = T

t1+t2 = 0.25

You have to apply the formula d=vt before and after the nap:

-Before the nap, the distance traveled was 0.50 km

0.50 = v1t1

-Afer the nap, the distance traveled was 3.50 km

3.50=v2t2

But v2=2v1 (because after the nap the rabbit runs twice as fast)

You have to solve the system of equations:

t1=0.25-t2 (I)

v1t1=0.50 (II)

2v1t2=3.50 (III)

Replacing (I) in (II)

v1(0.25-t2)=0.50

Applying distributive property and solving:

0.25v1-v1t2=.050

For (III) you have that v1t2=3.50/2=1.75. Hence:

0.25v1-1.75=0.50

Solving for v1:

v1 = 9 km/h

7 0

2 years ago