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SVEN [57.7K]
2 years ago
14

The average starting salary for this year's graduates at a large Texan university is $45,000, with a standard deviation of $4,00

0. Furthermore, it is known that the starting salaries re normally distributed. What is the probability that a randomly selected graduate will have a starting salary of $50,000? Please determine the Z value.
Business
1 answer:
4vir4ik [10]2 years ago
7 0

Answer:

The probability that a randomly selected graduate will have a starting salary of $50,000 or more is 10.56%

Explanation:

The formula for calculating a z-score is:

Z=\frac{x-μ}{σ}

Where:

x=Score in this case is $50,000

μ=Mean or average of the salary: $45,000

σ= standard deviation of $4,000.

Z=\frac{50000-45000}{4000}

Z= 1.25

This value has an associated probability of 0.8944= 89.44%, this means 89.44% of graduates will have a starting salary of $50,000 or less.

But if we want to know the probability that the graduate has a salary of $50,000 or more, taking into account a population of 100%=1

1-0.8944= 0.1056

Which represents that 10.56% of population of graduates will earn $50,000 or  more.

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Residual Income The operating income and the amount of invested assets in each division of Otte Industries are as follows: Opera
igomit [66]

Answer: See explanation

Explanation:

The residual income for each division will be calculated as follows:

Retail division:

Operating income = $8,000,000

Less: Minimum acceptable operating income as a percentage of invested assets = 10% × $40,000,000 = $4,000,000

Residual income = $4,000,000

Commercial division:

Operating income = $12,750,000

Less: Minimum acceptable operating income as a percentage of invested assets = 10% × $75,000,000 = $7,500,000

Residual income = $5,250,000

Internet division:

Operating income = $270,000

Less: Minimum acceptable operating income as a percentage of invested assets = 10% × $1,800,000 = $180,000

Residual income = $90,000

From the information above, we can also see that the commercial division has the highest residual value.

3 0
2 years ago
Christie and Jergens formed a partnership with capital contributions of $360,000 and $460,000, respectively. Their partnership a
Orlov [11]

Answer:

Christie's share is $104500 while Jergens share is $48500. Thus, the first option is the correct answer.

Explanation:

The appropriation of net income among the partners will be as follows,

                                              $                   $

Net Income                                          $153000

<u>Less: Salary to Partner</u>

Christie                                                  (66000)

<u>Less:Interest on Capital</u>

Christie                               36000

Jergens                              <u>46000        (82000)</u>

Remaining Profit                                     5000

<u>Distribution of Remaining Profit</u>

Christie  (5000/2 = 2500)                       2500

Jergens  (5000/2 =2500)                       <u>2500</u>

<u />

<u />

Christie's Share = 66000 + 36000 + 2500    = $104500

Jergen's share = 46000 + 2500   = $48500

5 0
2 years ago
In order to do an effective job, the CSIRT needs to know who it works for and what systems it should focus on; in other words, i
Viktor [21]

Answer:

Constituency

Explanation:

CSIRT stands for  Computer Security Incident Response Team, they are a group of experts that are hired to handle all incidents that occurred within your computer system.

In CSIRT term, constituency refers to area of expertise that each members of the team possess along with division of responsibilities that they have within the team . Having wider range of constituency tend to make the team become more efficient and capable to handle different types of attacks to the system.

7 0
2 years ago
Worldwide quarterly sales of a brand of cell phones were approximately q = −p + 136 million phones when the wholesale price was
Gre4nikov [31]

Answer:

$51

Explanation:

Data provided:

Sales function as: ( q = −p + 136 ) million phones

here, p is price in dollars

a) supply function as: ( q = 9p - 374 ) million phones

now,

for equilibrium price, the supply should be equal to the sales

i.e

−p + 136 = 9p - 374

or

136 + 374 = 9p + p

or

10p = 510

or

p = $51

Hence, the equilibrium price should be $51

8 0
2 years ago
Granite State Airlines serves the route between New York and Portsmouth, NH, with a single-flight-daily 100-seat aircraft. The o
TEA [102]

Answer:

Given data: One flight with total seats = 100

Full fare passengers, cost per ticket=$150, mean=56 passengers, SD=23

Discount fare passengers, cost per ticket=$100, mean=88 passengers, SD=44

(a) Here, though there is a hint to use the CDF, since the confidence interval is not given we will make some simplying assumptions that will reduce the complexity of the question, of course keeping the question statistically correct.

this question wants us to maximize total revenue per flight (one way), we can do that by taking only full fare passengers or total revenue will be 150*100=$15,000, but since historical probability shows a mean of 56 with a standard deviation of 23, we can assume in best case scenario total full fare ticket passengers will be 56+23=79, leaving 21 tickets for discount passenger, in this case the total revenues will be 79*150+21*100=$13,950

(b) Now, the new constrained policy is giving a clear cut number of seats to each category of pasengers, 44 for discount (total revenues 44*100) and 56 for full fare (total revenues 56*150) both of which are within the probabilities given earlier (full fare mean=56, discount mean=88). Total revenues in case will be 44*100+56*150=$12,800.

(c) Gain is the difference of the excess revenues in both cases of optimal total revenues and limited seats policy or answer (a) - answer (b) = $13,950- $12,800=$1,150

(d) Realistically speaking, there is no answer for this question without a clear cut confidence interval. Another simplifying assumption we can make here is taking the mean passengers as expected bookings (can be tweaked once confidence interval or degree of significance is given). so total revenues in this case will be 44*100 from discount and 56*150 from full fare passengers. That is still similar to answer (c) due to our assumption/lack of constraints, so our optimal booking will be 54 full fare tickets and 44 discount passenger tickets. You can also take worst case scenario by subtracting SD of each passenger type from the mean or go the best case scenario in which SD of full fare will be added to the mean while the pending seats (left over from 100) will be the total to discount fare for optimal revenue collection.

6 0
3 years ago
Read 2 more answers
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