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2 years ago

When you park on a hill, think about which way _____.

2 answers:

7 0

I don't see why this is on a computer section but either way I would chose D because naturally when you park on a hill you would be cautious about your car going into motion down the hill so therefore you would think of which way gravity would pull your vehicle

Anuta_ua [19.1K]2 years ago

6 0

Answer:

B. your vehicle would roll if an object fell on the accelerator

Explanation:

You might be interested in

Write a function string middle(string str) that returns a string containing the middle character in str if the length of str is

Katen [24]

Answer:

function getMiddle(s) {

return s.length % 2 ? s.substr(s.length / 2, 1) : s.substr((s.length / 2) - 1, 2);

}

// I/O stuff

document.getElementById("submit").addEventListener("click", function() {

input = document.getElementById("input").value;

document.getElementById("output").innerHTML = getMiddle(input);

});

Explanation:

// >>> is an unsigned right shift bitwise operator. It's equivalent to division by 2, with truncation, as long as the length of the string does not exceed the size of an integer in Javascript.

// About the ~ operator, let's rather start with the expression n & 1. This will tell you whether an integer n is odd (it's similar to a logical and, but comparing all of the bits of two numbers). The expression returns 1 if an integer is odd. It returns 0 if an integer is even.

// If n & 1 is even, the expression returns 0.

// If n & 1 is odd, the expression returns 1.

// ~n & 1 inverts those two results, providing 0 if the length of the string is odd, and 1 if the length of the sting is even. The ~ operator inverts all of the bits in an integer, so 0 would become -1, 1 would become -2, and so on (the leading bit is always the sign).

// Then you add one, and you get 0+1 (1) characters if the length of the string is odd, or 1+1 (2) characters if the length of the string is even.

6 0

2 years ago

How can we make our programs behave differently each time they are run?

tensa zangetsu [6.8K]

Answer:

By given the right speech as much as the answers must be

Explanation:

By given the right speech as much as the answers must be

7 0

1 year ago

Use the loop invariant (I) to show that the code below correctly computes the product of all elements in an array A of n integer

NeTakaya

Answer:

Given Loop Variant P = a[0], a[1] ... a[i]

It is product of n terms in array

Explanation:

The Basic Step: i = 0, loop invariant p=a[0], it is true because of 'p' initialized as a[0].

Induction Step: Assume that for i = n - 3, loop invariant p is product of a[0], a[1], a[2] .... a[n - 3].

So, after that multiply a[n - 2] with p, i.e P = a[0], a[1], a[2] .... a[n - 3].a[n - 2].

After execution of while loop, loop variant p becomes: P = a[0], a[1], a[2] .... a[n -3].a[n -2].

for the case i = n-2, invariant p is product of a[0], a[1], a[2] .... a[n-3].a[n-2]. It is the product of (n-1) terms. In while loop, incrementing the value of i, so i=n-1

And multiply a[n-1] with p, i.e P = a[0].a[1].a[2].... a[n-2].

a[n-1]. i.e. P=P.a[n-1]

By the assumption for i=n-3 loop invariant is true, therefore for i=n-2 also it is true.

By induction method proved that for all n > = 1 Code will return product of n array elements.

While loop check the condition i < n - 1. therefore the conditional statement is n - i > 1

If i = n , n - i = 0 , it will violate condition of while loop, so, the while loop will terminate at i = n at this time loop invariant P = a[0].a[1].a[2]....a[n-2].a[n-1]

6 0

2 years ago

Miles to track laps One lap around a standard high-school running track is exactly 0.25 miles. Write a program that takes a numb

fredd [130]

Answer:

Explanation:

#include <iostream>

using namespace std;

//This is the function in the next line

double MilesToLaps(double userMiles) {

double Laps;

Laps = userMiles * 4;

return Laps

}

//This is the main fucnction

int main(){

double Miles, FinLap;

cout << "Enter the number of miles " << endl;

cin>>Miles;

FinLap = MilesToLaps(Miles);

cout << "The number of laps ran is: "<<setprecision(2)<<Finlap<<endI;

}

3 0

2 years ago

Read 2 more answers

The groups_per_user function receives a dictionary, which contains group names with the list of users. Users can belong to multi

Akimi4 [234]

The groups_per_user function receives a dictionary, which contains group names with the list of users.

Explanation:

The blanks to return a dictionary with the users as keys and a list of their groups as values is shown below :

def groups_per_user(group_dictionary):

user_groups = {}

# Go through group_dictionary

for group,users in group_dictionary.items():

# Now go through the users in the group

for user in users:

# Now add the group to the the list of

# groups for this user, creating the entry

# in the dictionary if necessary

user_groups[user] = user_groups.get(user,[]) + [group]

return(user_groups)

print(groups_per_user({"local": ["admin", "userA"],

"public": ["admin", "userB"],

"administrator": ["admin"] }))

3 0

2 years ago