Answer:
CPU need 50% much faster
disk need 100% much faster
Explanation:
given data
workload spend time CPU = 60%
workload spend time I/O = 40%
achieve overall system speedup = 25%
to find out
How much faster does CPU need and How much faster does the disk need
solution
we apply here Amdahl’s law for the overall speed of a computer that is express as
S =
.............................1
here f is fraction of work i.e 0.6 and S is overall speed i.e 100% + 25% = 125 % and k is speed up of component
so put all value in equation 1 we get
S =
1.25 =
solve we get
k = 1.5
so we can say CPU need 50% much faster
and
when f = 0.4 and S = 125 %
put the value in equation 1
S =
1.25 =
solve we get
k = 2
so here disk need 100% much faster
In java...
public boolean checkSquare(int n){
int actualNumber = n;
int squareRoot = (int)Math.sqrt(n);
int squaredNumber = Math.pow(squareRoot,2);
if(squaredNumber==actualNumber){
return true;
} else {
return false;
}
}
This type of security failure is called WIN32K_SECURITY_FAILURE. <span> This indicates a </span>security failure was detected in win32k. <span>According to a new report issued by Dark Reading, there are a number of key </span>security failures<span> that cybercriminals take advantage of.</span>
Answer:
Pseudo CODE
a)
n= Input “Enter 5 integer value”
b)
sum=0.0
For loop with i ranging from 0 - 5
Inside loop sum=n[i]+sum
Outside loop avg= sum/5
Print avg
c)
small=n[0] # assume the first number in the list is smallest
large= n[0] # assume the first number in the list is largest
For loop with i ranging from 0 - 5
Inside loop if n[i]<small #if any another number is smaller than small(variable)
Inside if Then small=n[i]
Inside loop if n[i]>large # if any another number is larger than large(variable)
Inside if then large=n[i]
Print small
Print large
d)
print avg
print small
print large
<span>In the scenario in which the IT department is reporting that a company web server is receiving an abnormally high number of web page requests from different locations simultaneously the DDoS security attack is occurring.
</span>DDos stands for Distributed Denial of Service<span> . This </span><span>attack is an attempt to make an online service unavailable by overwhelming it with traffic from multiple sources.</span>