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Vedmedyk [2.9K]
2 years ago
6

The amount of nitrogen in an organic substance can be determined by an analytical method called the Kjeldahl method, in which al

l the nitrogen in the organic substance is converted to ammonia. The ammonia, which is a weak base, can be neutralized with hydrochloric acid, as described by the equation NH3(aq)+HCl(aq)⟶NH4Cl(aq) NH3(aq)+HCl(aq)⟶NH4Cl(aq) If 88.0 mL88.0 mL of 0.150 M HCl(aq)0.150 M HCl(aq) is needed to neutralize all the NH3(g)NH3(g) from a 2.25 g sample of organic material, calculate the mass percentage of nitrogen in the sample.
Chemistry
1 answer:
aev [14]2 years ago
8 0

<u>Answer:</u> The mass percent of nitrogen in the sample is 8.2 %

<u>Explanation:</u>

Kjeldahl method is defined as the analytical method which is used in the determination of nitrogen content in any organic compound.

In this method, nitrogen is converted into ammonia and the ammonia formed is then reacted with an acid.

The chemical equation for the reaction of ammonia with hydrochloric acid follows:

NH_3(aq.)+HCl(aq.)\rightarrow NH_4Cl(aq.)

To calculate the percentage of nitrogen in the organic compound, we use the equation:

\% \text{ nitrogen in sample}=\frac{(1.4\times M_1V_1)}{w}

where,

M_1 = molarity of acid used = 0.150 M

V_1 = Volume of acid used (in mL) = 88.0 mL

w = mass of sample = 2.25 g

Putting values in above equation, we get:

\% \text{ nitrogen in sample}=\frac{(1.4\times 0.150\times 88.0)}{2.25}\\\\\% \text{ nitrogen in sample}=8.2\%

Hence, the mass percent of nitrogen in the sample is 8.2 %

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2 years ago
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Answer:

0.921 J/g degrees C

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Recall that the First Law of Thermodynamics demands that the total internal energy of an isolated system must remain constant. Any amount of energy lost by the brakes must be gained by the tires (in the form of heat in this situation).  Therefore, heat given off by the brakes = −heat taken in by tires, or:

−qbrakes=qtires

The equation used to calculate the quantity of heat energy exchanged in this process is:

−qbrakes=−cbrakes mbrakes ΔTbrakes=ctires mtires ΔTtires=qtires

First we must convert the mass of the tires and the brakes from  kg to  g.

massbrakes=90.7 kg×1,000. g1 kg=9.07×104 g

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Next, substitute in known values and rearrange to solve for ctires. Note that the final temperature for both the tires and the brakes is 172∘C, the initial temperature of the brakes is 312∘C and the initial temperature of the tires is 15∘C.

−(1.400Jg∘C)(9.07×104 g)(172∘C−312∘C)=(ctires)(1.23×105 g)(172∘C−15∘C)

ctires=−(1.400 Jg∘C)(9.07×104 g)(−140∘C)(1.23×105 g)(157∘C)=17,777,200 J19311000 g∘C=0.9206Jg∘C

The answer should have three significant figures, so round to 0.921Jg∘C.

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So, according to the balanced equation, it can be seen that rate of formation of Cl^{-} will be twice the rate of disappearance of H_{2}S .

And, it is known that rate of disappearance of reactant will be negative and rate of formation of products will be positive value.

This means that,

Rate of the reaction = -Rate of disappearance of H_{2}S

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Therefore, calculate the rate of formation of Cl^{-} as follows.

Rate of formation of Cl^{-} = 2 \times 1.96 \times 10^{-7}

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2 years ago
What is the 2s in 42,256
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42,256 = 2,000

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