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malfutka [58]
2 years ago
11

Given the equation: ch4 + br2 → ch3br + hbr which type of reaction does this equation represent

Chemistry
2 answers:
xeze [42]2 years ago
7 0

Answer : The given equation represents "Substitution reaction" of alkanes

Explanation :

The given reaction is,

CH_{4}+ Br_{2}\rightarrow CH_{3}Br + HBr

To find out the type of reaction, we need to look at the reactants and products involved in the reaction

CH₄ is an alkane known as methane and Br₂ is bromine which belongs to halogen family.

During the reaction , we can see that one of the H atoms of methane is substituted by Br to form a product CH₃Br.

Therefore this is a "substitution reaction of alkanes" Since a hydrogen atom gets replaced by a halogen atom, it is also termed as "halogenation of alkanes"

mr Goodwill [35]2 years ago
5 0
Sh!!!!!eeeetttt iidkkk 
i got the same question on my chem hw and im d y i n g 
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Type the correct answer in the box. Express the answer to three significant figures.
frutty [35]

Answer : The energy released is -3319.7 KJ.

Solution : Given,

Mass of methane = 59.7 g

Molar mass of methane = 16 g/mole

\Delta H=-890KJ/mole

The value of \Delta H is in negative that means the energy is releasing.

First we have to calculate the moles of methane.

Moles of methane = \frac{\text{ Mass of methane}}{\text{ Molar mass of methane}}= \frac{59.7g}{16g/mole}=3.73moles

Now we have to calculate the amount of energy released.

The given reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the reaction, we conclude that

1 mole of methane releases -890 KJ/mole of energy

3.73 moles of methane releases \frac{-890KJ/mole}{1mole}\times 3.73mole=-3319.7KJ of energy

Therefore, the energy released is -3319.7 KJ.

5 0
2 years ago
Tritium 3 1H decays to 3 2He by beta emission. Find the energy released in the process. Answer in units of keV.
-Dominant- [34]

Answer:

The energy released in the decay process = 18.63 keV

Explanation:

To solve this question, we have to calculate the binding energy of each isotope and then take the difference.

The mass of Tritium = 3.016049 amu.

So,the binding energy of Tritium =  3.016049 *931.494 MeV

= 2809.43155 MeV.

The mass of Helium 3 = 3.016029 amu.

So, the binding energy of Helium 3 = 3.016029 * 931.494 MeV

= 2809.41292 MeV.

The difference between the binding energy of Tritium and the binding energy of Helium is: 32809.43155 - 2809.412 = 0.01863 MeV

1 MeV = 1000keV.

Thus, 0.01863 MeV = 0.01863*1000keV = 18.63 keV.

So, the energy released in the decay process = 18.63 keV.

7 0
2 years ago
Calculate the amount of heat necessary to raise the temperature of 135.0 g of water from 50.4°F to 85.0°F. The specific heat of
MAXImum [283]

Here we have to calculate the heat required to raise the temperature of water from 85.0 ⁰F to 50.4 ⁰F.

10.857 kJ heat will be needed to raise the temperature from 50.4 ⁰F to 85.0 ⁰F

The amount of heat required to raise the temperature can be obtained from the equation H = m×s×(t₂-t₁).

Where H = Heat, s  =specific gravity = 4.184 J/g.⁰C, m = mass = 135.0 g, t₁ (initial temperature) = 50.4 ⁰F or 10.222 ⁰C and t₂ (final temperature) = 85.0⁰F or 29.444 ⁰C.

On plugging the values we get:

H = 135.0 g × 4.184 J/g.⁰C×(29.444 - 10.222) ⁰C

Or, H = 10857.354 J or 10.857 kJ.

Thus 10857.354 J or 10.857 kJ heat will be needed to raise the temperature.

6 0
2 years ago
Write an equation that shows the formation of a strontium ion from a neutral strontium atom
Pepsi [2]

Answer:

See explanation

Explanation:

Sr(s) + 2HCl(aq) -----> SrCl2(aq) + H2(g)

Ionically;

Sr(s) + 2Cl^-(aq) ----> SrCl2(aq)

If we look at the reaction above, strontium atom was dissolved in hydrochloric acid. The strontium atom is now oxidized by the acid to give Sr^2+ ion according to the equation shown above.

3 0
2 years ago
65g of nitric acid are produced in a reaction. 2.5g of platinum are added to the reaction vessel at the start of the reaction to
AysviL [449]

Answer:

2.5 g of platinum

Explanation:

Recall that a catalyst is a specie added to a reaction system to increase the rate of reaction. A catalyst does not participate in the chemical reaction hence it remains unchanged at the end of the chemical reaction. A catalyst merely provides an alternative reaction pathway by lowering the activation energy of the reaction system. Hence a catalysed reaction usually proceeds faster with less energy requirement than the uncatalysed reaction.

Since the catalyst does not participate in the reactions and remains unchanged at the end of the reaction, the mass of platinum will remain the same (2.5g). The mass can only change if a specie participates in the chemical reaction. Hence the answer.

6 0
2 years ago
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