A). because the roots are shown. The roots of this quadratic function would be x=2, and x=-2
The Mean = (135 + 71 + 69 + 80 + 158 + 152 + 161 + 96 + 122 + 118 + 87 + 85 ) : 12 = 111.166
The smallest value : 69
The greatest value : 161
s² = ∑( x i - x )² / ( n - 1 )
s² = ( 568.274 + 1613.3 + 1777.97 + 971.32 + 2193.42 + 1667.4 + +2483.42 + 230 + 117.38 + 46.7 + 584 + 684.66 ) : 11
s² = 1176.1676
s = √s² = √1176.1676
s ( Standard deviation ) = 34.295
All the values fall within 2 standard deviations:
x (Mean) - 2 s and x + 2 s
Answer:
Option D (-4,7)
Step-by-step explanation:
we have
Square TUVW with vertices T(-6,1), U(-1,0), V(-2,-5), and W(-7,-4
<u><em>The question is</em></u>
Find out the coordinates of U'
Part a) Reflection: in the y-axis
we know that
The rule of the reflection of a point across the y-axis is
(x,y) -----> (-x,y)
so
U(-1,0) -----> U'(1,0)
Part b) Translation (x,y) —> (x-5,y+7)
That means ---> the translation is 5 units at left and 7 units up
so
U'(1,0) -----> U''(1-5,0+7)
U'(1,0) -----> U''(-4,7)
therefore
Option D (-4,7)
Answer: The average number of hours she danced per day is 1.9 hours (rounded to the nearest tenth)
Step-by-step explanation: We start by calculating how many hours she danced all together which can be derived as follows;
Summation = 3 +2 +2 + 1 + 1.5 + 2 = 11.5
The number of days she danced which is the observed data is 6 days (she did not dance at all on Wednesday).
The average (or mean) hours she danced each day can be calculated as
Average = ∑x ÷ x
Where ∑x is the summation of all data and x is number of observed data
Average = (3+2+2+1+1.5+2) ÷ 6
Average = 11.5 ÷ 6
Average = 1.9166
Approximately, average hours danced is 1.9 hours (to the nearest tenth)