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Sliva [168]
2 years ago
10

In the diagram, AngleTRV ≅ AngleVRW. 2 lines intersect. A line with points T, R, W intersects a line with points S, R, V at poin

t R. What is the measure of AngleSRT? mAngleSRT = degrees
Mathematics
2 answers:
BabaBlast [244]2 years ago
8 0

Answer:

The measure of angle TRV is 130° ⇒ last answer

Step-by-step explanation:

* According to the attached graph

- Line TRW intersects line SRV at point R

- The measure of angle VRT is (2x + 10)°

- The measure of angle VRW is (x - 10)°

- We need to find measure of angle TRV

- From the attached figure

∵ T , R , W lie on the same line

∴ ∠TRW is a straight angle

- The measure of the straight angle is 180°

∴ m∠TRW = 180°

∵ ∠TRW contains ∠VRT and ∠VRW

∴ m∠VRT + m∠VRW = m∠TRW

∴ m∠VRT + m∠VRW = 180°

∵ m∠VRT = (2x + 10)°

∵ m∠VRW is (x - 10)°

∴ 2x + 10 + x - 10 = 180

- Add like terms

∴ 3x = 180

- Divide both sides by 3

∴ x = 60

∵ m∠TRV = (2x + 10)°

- Substitute x by 60

∴  m∠TRV = 2(60) + 10 = 120 + 10 = 130°

∴ The measure of angle TRV is 130°

barxatty [35]2 years ago
5 0

Answer:

90 Degrees, the answer is just 90 Degrees

Step-by-step explanation:

I took the test

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Margo bought 7 pens from a bookstore. Some of the pens cost $3 each, and the rest cost $4 each. If she paid a total of $23 for t
e-lub [12.9K]

Answer: 5 Pens!

Step-by-step explanation: 5 Pens Would Be The Answer.

8 0
2 years ago
You need to write an essay that has at least 500 words you have written 285 words so far right and solve an inequality that Reec
andrezito [222]

Answer:

The minimum number of words left to write is 215

Step-by-step explanation:

Let

w -----> the number of words left to write

we know that

The number of words left to write plus the words written so far must be greater than or equal to 500 words

Remember that the word "at least" means "greater than or equal to"

so

w+285\geq 500                

Solve for w                        

Subtract 285 both sides        

w\geq 500-285\\w\geq 215

The minimum number of words left to write is 215

3 0
2 years ago
What is the geometric mean of 3 and 147
Makovka662 [10]

multiply the two numbers together, then take the square root

3* 147

441

sqrt(441)

21

The geometric mean is 21

3 0
2 years ago
A survey of 225 students showed the mean number of hours spent studying per week was 20.6 and the standard deviations was 2.7
LekaFEV [45]

Answer:

The margin of error is approximately 0.3

Step-by-step explanation:

The following information has been provided;

The sample size, n =225 students

The sample mean number of hours spent studying per week = 20.6

The standard deviation = 2.7

The question requires us to determine the margin of error that would be associated with a 90% confidence level. In constructing confidence intervals of the population mean, the margin of error is defined as;

The product of the associated z-score and the standard error of the sample mean. The standard error of the sample mean is calculated as;

\frac{sigma}{\sqrt{n} }

where sigma is the standard deviation and n the sample size. The z-score associated with a 90% confidence level, from the given table, is 1.645.

The margin of error is thus;

1.645*\frac{2.7}{\sqrt{225}}=0.2961

Therefore, the margin of error is approximately 0.3

5 0
2 years ago
Read 2 more answers
Question 6: An experiment consists of throwing two six-sided dice and observing the number of spots on the upper faces. Determin
yaroslaw [1]

Answer:

(a) 0.25

(b) 0.944

(c) 0.444

(d) 0.167

Step-by-step explanation:

There are six possible outcomes for each die, which means that the number of possible outcomes is:

n=6*6 = 36

(a) In order for each die to show four or more spots they will both have to land on a four, five or six. The probability of this happening is:

P(A) = \frac{3*3}{36}=0.25

(b) There are only two possible outcomes for which the sum is three (1 and 2, or 2 and 1). The probability of the sum NOT being three is:

P(B) = 1-\frac{2}{36}=0.944

(c) If neither a one or a six must appear, then there are 4 possible outcomes for each die, the probability is:

P(C) = \frac{4*4}{36}=0.444

(d) For each one of the six possible numbers on the first die, there is only one on the second die for which the sum of the spots is 7, totaling six possible ways to sum 7:

P(D) = \frac{6}{36}=0.167

7 0
2 years ago
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