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s2008m [1.1K]
1 year ago
14

Line J M is the perpendicular bisector of LK.

Mathematics
2 answers:
Ira Lisetskai [31]1 year ago
4 0

Answer:

LN and NK

Step-by-step explanation:

edu 2020 the lines are liner so that means the 2 that are congruent because l goes to n the through n straight to k no turns a line  

jolli1 [7]1 year ago
3 0

Answer:

LN and NK

Step-by-step explanation:

A perpendicular bisector of a line segment divides the line segment into 2 equal halves.

Here, line JM is a perpendicular bisector of line segment LK at point N. So, line JM divides the line segment LK into 2 equal halves.

The two equal halves are segment LN and segment NK.

Therefore, segment LN is congruent to segment NK.

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It cost Jayden $4.80 to send 96 text messages. How much would it cost to send 155 text messages?
TEA [102]
96 messages .... $4.80
155 messages .... x

x= (155x4.80):96=7.75
3 0
1 year ago
Of the 400 eighth-graders at pascal middle school, 117 take algebra, 109 take advanced computer, and 114 take industrial technol
Hatshy [7]

If 164 of the 400 eighth-graders take none of these courses, then 400-164=236 students take some courses.

Let x students take all three courses, then:

1. 70-x take only both algebra and advanced computer,

2. 34-x take only both algebra and industrial technology,

3. 29-x take only both advanced computer and industrial technology.

Now let's count how many student take only one course:

1. 117-(x+34-x+70-x)=13+x take algebra,

2. 109-(x+29-x+70-x)=10+x take advanced computer,

3. 114-(x+29-x+34-x)=51+x take industrial technology.

Now count all students that take some courses:

51+x+10+x+13+x+29-x+34-x+70-x+x=236,

x=236-51-10-13-29-34-70,

x=29.

Answer: all three courses take 29 students.

6 0
1 year ago
Read 2 more answers
The quotient of 15 and a number is 1 over 3 written as an equation
Agata [3.3K]

Answer:

15/x=1/3

Step-by-step explanation:

The quotient of 15 and a number=15/x=1/3

15/x=1/3


6 0
1 year ago
To a survey of 290 newspaper reader, 181
astra-53 [7]

Question:

To a survey of 290 newspaper readers, 181 of them read the Daily Times, 142 Read the Guardian 117 read punch and each reads at least one of the three papers if 75 read the Daily Times, and the Guardian, 60 read the Daily Times and punch, and 54 read the Guardian and punch : Draw a Venn diagram to illustrate this information How many readers read All three papers ,Exactly two of the papers The Guardian alone?

Answer:

39 read all three news papers,72 Exactly two Papers & 52 reads  Guardian Alone

Step-by-step explanation:

We have given, A survey of 290 newspaper readers.

Who read the Daily times A=181  

Who read the Guardian times B=142  

Who read the punch C=117

Who read Daily Times and the Guardian A\cap B= 75

Who read Daily Times and the punch A\cap C=60

Who read Guardian and punch B\cap C=54

To find :

How many readers read All three papers, Exactly two of the papers The Guardian alone?

Solution :

Readers read all three papers is A\cap B\cap C

Total survey is given by,

Total = A+B + C- A\cap B- A\cap C - B\cap C+ A\cap B\cap C

290 = 181 + 142 + 117 - 75 -60 - 54 +A\cap B\cap C

290 =251+A\cap B\cap C

290-251=A\cap B\cap C

A\cap B\cap C=39

So, number of readers who read all three papers is 39.

Exactly two of the papers = 36 + 21 + 15 = 72

Guardian Alone = 52

7 0
1 year ago
Please help!! I need to get this done! Im begging you, brainliest and points!
Viefleur [7K]

Answer:

<em>Solution; ( 1, 0 ), and ( - 3, 4 )</em>

Step-by-step explanation:

See procedure below;

First let us make these two functions ( y = -x + 1 , y = x^2 + x - 2 ) equivalent;

- x + 1  = x^2 + x - 2,

-x - x + 1 + 2 - x^2 = 0,

- 2x + 3 - x^2 = 0,

x^2 + 2x - 3 = 0,

Now factor the simplified equation;

x^2 + 2x - 3 = 0,

( x^2 - x ) + ( 3x - 3 ) = 0,

x ( x - 1 ) + 3 ( x - 1 ) = 0,

( x - 1 )( x + 3 ) = 0,

And solve for x;

x - 1 = 0, and x + 3 = 0,

x = 1, and x = - 3

Now substitute this value of x into the two functions as to receive the y  values for each x - value;

y = - ( 1 ) + 1, <em>y = 0 for x = 1</em>,

y = ( - 3 )^2 - 3 - 2, y = 9 - 3 - 2, <em>y = 4 for x = - 3</em>,

<em>Solution; ( 1, 0 ), and ( - 3, 4 )</em>

8 0
1 year ago
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