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Alenkasestr [34]
2 years ago
13

Jude has 5 pairs of sunglasses that cost the same in his online shopping cart, then decides to get only 2. Each pair of sunglass

es is the same price. Let p represent the cost of each pair. Write an expression for the original cost, and the difference in cost.
Mathematics
1 answer:
hoa [83]2 years ago
5 0

Answer:

Step-by-step explanation:

5p is the original price

Then 2p is the new price

5p-2p=3p

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A population consists of 500 elements. We want to draw a simple random sample of 50 elements from this population. On the first
larisa [96]

Answer:

D. 0.002

Step-by-step explanation:

Given;

total number of sample, N = 500 elements

50 elements are to be drawn from this sample.

The probability of the first selection, out of the 50 elements to be drawn will be = 1 / total number of sample

The probability of the first selection = 1 / 500

The probability of the first selection = 0.002

Therefore, on the first selection, the probability of an element being selected is 0.002

The correct option is "D. 0.002"

4 0
2 years ago
John Birks "Dizzy" Gillespie (1917-1993) was a trumpeter and was extremely influential in the development of bebop. Also an acco
Nikitich [7]

Answer:

  • <em><u>"Ambassador of Jazz"</u></em>

Explanation:

<em>John Birks "Dizzy" Gillespie</em> (1917 – 1993) is recognized as an extraordinary trumpet player who had tremendous influence in the modern jazz and the development of the new music style called bebop.

<em>Bebop</em> required instrumental virtuosity and creativity to improvise as it involves fast tempo, and numerous of rapid changes of chords and keys. Personal characteristics that Gillispie had in excess.

As you can find in the internet, the nickname of "Ambassador of Jazz" was given to him in 1956, during a State Department tour of the Middle East that he succesfully organized.

Gillespie was a leader in music and an innovator who greatly influenced the musical development of this genre. He played along with other important jazz and bebop players of his time.

3 0
1 year ago
A marketing firm is considering making up to three new hires. Given its specific needs, the management feels that there is a 50%
IRISSAK [1]

Answer:

a) 0.9

b) Mean = 1.58

Standard Deviation = 0.89

Step-by-step explanation:

We are given the following in the question:

A marketing firm is considering making up to three new hires.

Let X be the variable describing the number of hiring in the company.

Thus, x can take values 0,1 ,2 and 3.

P(x\geq 2) = 50\%= 0.5\\P(x = 0) = 10\% = 0.1\\P(x = 3) = 18\% = 0.18

a) P(firm will make at least one hire)

P(x\geq 2) = P(x=2) + P(x=3)\\0.5 = P(x=2) + 0.18\\ P(x=2) = 0.32

Also,

P(x= 0) +P(x= 1) + P(x= 2) + P(x= 3) = 1\\ 0.1 + P(x= 1) + 0.32 + 0.18 = 1\\ P(x= 1) = 1- (0.1+0.32+0.18) = 0.4

\text{P(firm will make at least one hire)}\\= P(x\geq 1)\\=P(x=1) + P(x=2) + P(x=3)\\ = 0.4 + 0.32 + 0.18 = 0.9

b) expected value and the standard deviation of the number of hires.

E(X) = \displaystyle\sum x_iP(x_i)\\=0(0.1) + 1(0.4) + 2(0.32)+3(0.18) = 1.58

E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89

7 0
1 year ago
Simplify the expression: sin(7x/3)cos(5x/2) - cos(7x/3)sin(5x/2)
monitta
Ok no need to worry
3 0
2 years ago
A psychologist is collecting data on the time it takes to learn a certain task. For 50 randomly selected adult subjects, the sam
tatuchka [14]

Answer: (15.263,\ 17.537)

Step-by-step explanation:

According to the given information, we have

Sample size : n= 50

\overline{x}=16.40

s=4.00

Since population standard deviation is unknown, so we use t-test.

Critical value for  95 percent confidence interval  :

t_{n-1,\alpha/2}=t_{49, 0.025}= 2.009575\approx2.010

Confidence interval : \overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}

16.40\pm (2.010)\dfrac{4}{\sqrt{50}}\\\\=16.40\pm1.13702770415\\\\=16.40\pm1.1370\\\\=(16.40-1.1370,\ 16.40+1.1370)\\\\=(15.263,\ 17.537)

Required 95% confidence interval :  (15.263,\ 17.537)

8 0
1 year ago
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