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2 years ago

maisie is 5 years younger than kyle, kyle is 2 years older than sam. if sam is 8 years old, how old is maisie

Mathematics

1 answer:

77julia77 [94]2 years ago

8 0

Answer:

Maisie is 5 years old hope this helps

Step-by-step explanation:

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-2(x-3y)=18 Solve for y

Inga [223]

Answer:

...The answer is y=3+x/3

7 0

2 years ago

Read 2 more answers

If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

8 0

2 years ago

jonathan bought a new computer for $2,016, using the electronics store's finance plan. he will pay $112 a month for 18 months. w

vekshin1

Y - the money he still owes,
x - the number of months ( from x = 0 to x = 18 ):
y = 2,016 - 112 x

6 0

2 years ago

John should drive to his workplace and back to home. On the way to the workplace it was raining, so he drove at speed of 42mph.

elixir [45]

Answer:

47.25 mph

Step-by-step explanation:

Represent the total distance traveled as 2x. Average speed= total distance/total time

When going at 42 mph, the time would be x/42 and when going at 54 mph the time would be x/54 to travel x distance. Add x/42 and x/54 together to get 16x/378. Then divide 2x by 16x/378 to get 47.25 mph. Also this is RSM innit?

5 0

2 years ago

11) The Cost of maintaing a

dezoksy [38]

Answer:

a). Cost of 44 pupils = $14265

b). Least number of pupils = 31

Step-by-step explanation:

The given question is incomplete; here is the complete question.

The cost of maintaining a school is partly constant and partly varies as the number of pupils. With 50 pupils, the cost is $15,705.00 and with 40 pupils, it is $13,305.00.

(a) Find the cost when there are 44 pupils.

(b) If the fee per pupil is $360.00, what is the least number of pupils for which the school can run without a loss?

Let the equation representing the total cost of maintaining a school is,

C = ax + b

Where C = Total cost of maintaining a school

a = Fee per pupil

b = Fixed running cost

x = number of pupils

a). Cost of 50 pupils = $15705

Equation will be,

15705 = 50a + b -------(1)

Cost of 40 pupils = $13305

Equation will be,

13305 = 40a + b --------(2)

By subtracting equation (2) from equation (1),

15705 - 13305 = (50a + b) - (40a + b)

2400 = 10a

a = 240

From equation (1),

b = 3705

Equation representing the total cost will be,

C = 240x + 3705

If x = 44

C = 240(44) + 3705

C = $14265

b). If the fee per pupil 'a' = $360

Let the number of pupils = p

Total fee of 'p' pupils = $360p

Total cost to run the school will be = 3705 + 240p

For the school not to be in the loss,

360p ≥ 3705 + 240p

360p - 240p ≥ 3705

120p ≥ 3705

p ≥ $\frac{3705}{120}$

p ≥ 30.875

Therefore, to run the school without loss, number pupils should be at least 31.

3 0

2 years ago

maisie is 5 years younger than kyle, kyle is 2 years older than sam. if sam is 8 years old, how old is maisie​

maisie is 5 years younger than kyle, kyle is 2 years older than sam. if sam is 8 years old, how old is maisie