Explanation:
75 J
Energy is neither related nor destroyed- it's simply converted to different forms. Forces are vectors with both mass and acceleration; they are interactions that have the ability to change an object's motion. As objects move, their potential energy (apprx 100 J) is converted to kinetic energy. However, friction a resistive force, which is formed from the conversion of an object's kinetic energy into heat energy, as two surfaces move along each other.
With the reduction of friction, the energy output should increase, as less energy is lost as heat. Thus, the output should be 75 J.
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Answer:
Frequency of B allele is 0.6681
Explanation:
If p represents the frequency of dominant allele and q represents the frequency of recessive allele, according to Hardy-Weinberg equilibrium:
p + q = 1
p² + 2pq + q² = 1
where p² = frequency of homozygous dominant genotype
q² = frequency of homozygous recessive genotype
2pq = frequency of heterozygous genotype
Given that number of recessive chestnut horse = 28
Total horses = 226 + 28 = 254
frequency of b² genotype = 28/254 = 0.1102
frequency of recessive b allele = √0.1102 = 0.3319
So, frequency of B allele =
1 - 0.3319 = 0.6681
Hence frequency of B allele is 0.6681
Answer:
D 2 million years is the answer
Explanation:
Answer:
Recessive phenotype plant
Explanation:
If the plant has recessive genotype then it will be easy to identify because it will have the recessive phenotype. However if the plant has dominant phenotype it can either have homozygous genotype or heterozygous genotype. To confirm if the plant is homozygous or heterozygous, a test cross can be done with plant having recessive phenotype.
If our test plant is homozygous dominant, it will pass one dominant allele to the next generation and all the offspring would have dominant phenotype. If our test plant is heterozygous dominant it will pass one dominant allele to half of the offspring and one recessive allele to another half so 50% of next generation will have dominant phenotype and other 50% will have recessive phenotype.
Hence by test cross (cross with recessive phenotype plant) it is possible to determine the genotype of the uncharacterized pea plant.
