Proportion which can be used to represent equivalency of 3 feet in 1 yard and 12 feet in 4 yard is 3 : 1 : : 12 : 4
<h3><u>Solution:</u></h3>
Given that
There are 3 feet in one yard
And there are 12 feet in 4 yard
Number of feet in one yard = 3 that is feet : yard = 3 : 1
Number of feet in 4 yards = 12 that is feet : yard = 12 : 4
And 3 feet in 1 yard is equivalent to 12 feet in 4 yards means
That is 3 : 1 : : 12 : 4
A proportion is statement that two ratios are equal. It can be written in two ways: as two equal fractions a/b = c/d; or using a colon, a : b = c : d
Hence proportion which can be used to represent equivalency of 3 feet in 1 yard and 12 feet in 4 yard is 3 : 1 :: 12 : 4
<span>the graph that represents the compound inequality –3
< n < 1 is the straight line from -3 to 1 in which there is a hollow
circle in the -3 point and in the 1 point. This is because < means that the
possible values of n is only greater than -3 exluding -3 and less than -1
excluding -1</span>
Answer:
The proportion of student heights that are between 94.5 and 115.5 is 86.64%
Step-by-step explanation:
We have a mean 
and a standard deviation 
. For a value x we compute the z-score as 
, so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%
Over time, compound interest at any rate will outperform simple interest. When the rates are nearly equal to start with, compound interest will be greater in very short order. Here, it takes less than 1 year for compound interest to give a larger account balance.
In 30 years, the simple interest will be
... I = P·r·t = 12,000·0.07·30 = 25,200
In 30 years, the compound interest will be
... I = P·(e^(rt) -1) = 12,000·(e^(.068·30) -1) ≈ 80,287.31
_____
6.8% compounded continuously results in more total interest
Answer:
<u>The correct answer is that a student have to score 1.41 standard deviations above the mean to be publicly recognized.</u>
Step-by-step explanation:
For answering the question, we don't know the score mean of the National Financial Capability Challenge Exam and neither the population or number of students who take the exam. The only information provided is that the public recognition in this normal distribution is only for students that scores in the top 8%. In other words for students above 92% of the population.
With this information, we can go to a Z Score Table and check that for being on the top 8% (above the 92% of any population), your result must be 1.405 standard deviations above the mean.
<u>Rounding the answer to 2 decimal places, it's 1.41 standard deviations above the mean.</u>
