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2 years ago

What is 75.7 divided by 6.7

Mathematics

2 answers:

STALIN [3.7K]2 years ago

4 0

Answer:

11.3 rounded

Step-by-step explanation:

Vladimir79 [104]2 years ago

3 0

Answer:

11.2985075

Step-by-step explanation:

You might be interested in

For the sequence an = 2n + 1, identify the values of a0 = _____, a1 = _____, a2 = _____, and a3 = _____.

Tresset [83]

Answer:

Option A - $a_0= 2,a_1= 3,a_2= 5,a_3= 9$

Step-by-step explanation:

Given : For the sequence $a_n= 2^n + 1$

To find : Identify the values of following?

Solution :

The nth term of the sequence is $a_n= 2^n + 1$

Substitute n=0,1,2 and 3

When n=0,

$a_0= 2^0+ 1$

$a_0= 1+1$

$a_0=2$

When n=1,

$a_1= 2^1+ 1$

$a_1= 2+1$

$a_1=3$

When n=2,

$a_2= 2^2+ 1$

$a_2=4+1$

$a_2=5$

When n=3,

$a_3= 2^3+ 1$

$a_3= 8+ 1$

$a_3= 9$

Therefore, The value is $a_0= 2,a_1= 3,a_2= 5,a_3= 9$

So, Option A is correct.

4 0

2 years ago

If the size of the sample to be used in a particular test of attributes has not been determined by utilizing statistical concept

EleoNora [17]

Answer:

C) The auditor may or may not achieve the desired risk of assessing control risk too low.

Step-by-step explanation:

In a concept of risk sampling, if the sample size is chosen randomly in accordance with random selection procedures, the auditor may or may not achieve the desired risk of assessing risk too low. In other words the auditor may or may not achieve desired precision. This is because a samole chosen randomly may not represent the true population.

This depends largely on the sample size. If the sample size selected is too small, the allowance for sampling risk will be larger than what is required because it will lead to a large standard error of the mean

5 0

2 years ago

Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u

soldier1979 [14.2K]

$x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }$

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

$p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}$

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

$\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}$

$\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}$

$\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}$

Therefore:

$\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]$

Recall that at t=25, $p(25)=\dfrac { 5800 } {13} \approx 446.15$

Therefore:

$\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009$

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0

2 years ago

Two planes, which are 3400 miles apart, fly toward each other. Their speeds differ by 80mph. If they pass each other in 5 hours,

Andreas93 [3]

Answer : The speed of both planes is 61.25 mph and 18.75 mph respectively.

Explanation:

Let the speed of first plane be x mph

Let the speed of second plane be y mph

Since we have given that difference of speeds is 80 mph

i.e. x - y= 80 ( $Eq^n$ 1)

Distance between two planes = 3400 miles

As they are flying towards each other i.e. they are in the opposite direction.

So, Relative speed will be the sum of their speeds i.e.

Relative speed = x + y

And we know speed = $\frac{Distance}{Time}$

Speed= $\frac{3400}{80}$

⇒ Speed = 42.5 mph

Hence, Relative speed becomes 42.5 mph

⇒ x+y=42.5 ( $Eq^n$ 2)

Now, by using the elimination method of solving the system of equation, we have ,

x= 61.25 mph

and y = 18.75 mph

4 0

2 years ago

The class president collected data on 150 randomly selected 17-year-olds at his school. He surveyed students on if they had a jo

telo118 [61]

Answer:

Step-by-step explanation:

Part A can be seen in the attached picture below. Since there are 76 students that have both a license and a job we need to subtract 76 from each to get the amount that only have either a license or a job as seen in the table. Also we can see from the table that it sums up to 145 students, meaning that 5 students do not have neither a job or a license.

Part B, to calculate this we need to divide the amount of students that ONLY have a job by the total amount of students that have a job (since the rest of those students also have a license) Therefore:

17 / 93 = 0.1828

Now we can multiply this result by 100 to get the percentage.

0.1828 * 100 = 18.28%

8 0

2 years ago