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vfiekz [6]
2 years ago
11

A weather balloon is filled to a volume of 6000 L while it is on the ground, at a pressure of 1 atm and a temperature

Physics
2 answers:
matrenka [14]2 years ago
8 0

Answer:

17582.4 L

Explanation:

Ideal gas law:

PV = nRT

where P is absolute pressure,

V is volume,

n is number of moles,

R is universal gas constant,

and T is absolute temperature.

Since n is constant:

PV / T = PV / T

(1 atm) (6000 L) / (273 K) = (0.3 atm) V / (240 K)

V = 17582.4 L

mariarad [96]2 years ago
3 0

Answer:

17582.4 L

Explanation:

Correct on Edge2020.

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A cubical shell with edges of length a is positioned so that two adjacent sides of one face are coincident with the +x and +y ax
Bingel [31]

Answer:

Q = ba⁴ * ε₀

Explanation:

From Gauss's Law, we know that

flux Φ = Q / ε₀

where ε₀ = 8.85e-12 C²/N·m²

and also,

Φ = EAcosθ

The field is directed along the x-axis, so that all of the flux passes through the side of the cube at x = a. This means that θ = 0º, and thus

Φ = EAcos0

Φ = EA

E = bx² meanwhile, we are interested in the point where x = a, so we substitute and then

E = ba²

Since A = a² for the cube face, we have

Q / ε₀ = E * A

Q / ε₀ = ba² * a²

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5 0
2 years ago
A student is conducting a physics experiment and rolls four different-
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Answer:

<em>I think the answer is C</em>

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Explanation:

Its heavy but not too heavy

4 0
2 years ago
A proton moves along the x-axis with vx=1.0×107m/s. As it passes the origin, what are the strength and direction of the magnetic
Sunny_sXe [5.5K]

Answer:

Magnetic field will be ZERO at the given position

Explanation:

As we know that the magnetic field due to moving charge is given as

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so here we know that for the direction of magnetic field we will use

\hat B = \hat v \times \hat r

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\hat B = \hat i \times (\hat i + 0\hat j + 0\hat k)

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3 0
2 years ago
You are working on a laboratory device that includes a small sphere with a large electric charge Q. Because of this charged sphe
madam [21]

Answer:

the only effect it has is to create more induced charge at the closest points, but the net face remains zero, so it has no effect on the flow.

Explanation:

We can answer this exercise using Gauss's law

      Ф = ∫ e . dA = q_{int} / ε₀

field flow is directly proportionate to the charge found inside it, therefore if we place a Gaussian surface outside the plastic spherical shell.  the flow must be zero since the charge of the sphere is equal  induced in the shell, for which the net charge is zero. we see with this analysis that this shell meets the requirement to block the elective field

From the same Gaussian law it follows that if the sphere is not in the center, the only effect it has is to create more induced charge at the closest points, but the net face remains zero, so it has no effect on the flow , so no matter where the sphere is, the total induced charge is always equal to the charge on the sphere.

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2 years ago
You are driving to the grocery store at 20 m/s. You are 110m from an intersection when the traffic light turns red. Assume that
oksano4ka [1.4K]

As we know that reaction time will be

t = 0.50 s

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now from kinematics equation we will have

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so the acceleration required by brakes is -2 m/s/s

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v_f - v_i = at

0 - 20 = -2 (t)

t = 10 s

total time to stop the car is given as

T = 10 s + 0.5 s = 10.5 s

3 0
2 years ago
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