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spin [16.1K]
2 years ago
15

Reset the PhET simulation (using the button in the lower right) and set it up in the following manner: select Oscillate, select

No End, and use the parameters in parentheses by sliding the bars for Amplitude (1.00 cmcm), Frequency (1.40 HzHz ), Damping (none), and Tension (highest). Using the available Rulers, calculate the frequency of a photon that corresponds to the wavelength of the resulting wave. Assume the length with units (cmcm) of the ruler represents the real photon wavelength and that the speed of light is 3.00×108 m/s3.00×108 m/s.

Physics
1 answer:
lubasha [3.4K]2 years ago
5 0

Answer:

Check Explanation

Explanation:

This is a question that is as a result of an experimental procedure.

The Phet simulation is put on the settings given in the question;

- select Oscillate

- Select No End

- Use the parameters in parentheses by sliding the bars for Amplitude (1.00 cm), Frequency (1.40 Hz)

- Damping (none)

- Tension (highest)

I'll attach an interface of the Phet simulation to this solution.

Once all of these settings have been fixed, the simulation gives a wave pattern whose wavelength can be read from the ruler attached to the background of the simulation.

The wavelength is the distance from crest to crest or from trough to trough.

From the simulation example I have attached, the distance from crest to crest is from the green indicator on one crest to the green indicator on the next crest, that is about 5 to 5.1 cm

The velocity of a wave, v, is related to the frequency, f, and wavelength, λ of the wave through

v = fλ

For the photon, the velocity of the wave is the speed of light,

v = c = (3.00 × 10⁸) m/s

The wavelength computed from the simulation = λ = 5.1 cm = 0.051 m

c = fλ

frequency = (c/λ) = (3.00 × 10⁸) ÷ 0.051 = (5.88 × 10⁹) Hz

So, this step can be used to obtaim rhe required frequency of the photon, just follow these steps and use the calculation method too. You should be able to obtain the frequency of the photon in your experiment.

Hope this Helps!!!

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Answer:

Explanation:

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E = e Aσ ( T⁴ - T₀⁴ )

E is heat radiated , e is emissivity , A is area of surface , σ  is stephan's constant T is temperature of the object and T₀ is temperature of the surrounding .

For all the objects given , e , σ T and T₀ are same so E will solely dependent on area of the surface

surface area of cube= 6 r² ,

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= 12.56 r²

hemisphere = 2 π r²

= 6.28 r²

12.56 r² >6.28 r² > 6 r²

heat radiated by sphere > heat radiated by hemisphere > heat radiated by cube .

8 0
2 years ago
When you come within 100 ft of the uncontrolled railroad crossing and you cannot see the tracks for 400 ft in both directions, t
Sergio039 [100]
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6 0
2 years ago
The electric potential in a particular region of space varies only as a function of y-position and is given by the function V(y)
nikdorinn [45]

Answer:

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Explanation:

First let's find the electric potential using y = 22.5:

V(y) = 1.69y^2 +15.6y+52.5

V(22.5) = 1.69(22.5)^2 + 15.6*22.5 + 52.5

V(22.5) = 1259.0625\ Volts

Then, to find the magnitude of the electric field, we just need to divide the electric potential by the distance y:

E = V/d

E = 1259.0625/22.5

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3 0
2 years ago
If a current of 2.4 a is flowing in a cylindrical wire of diameter 2.0 mm, what is the average current density in this wire?
Gnom [1K]

The average current density in the wire is given by:

J=\frac{I}{A}

where I is the current intensity and A is the cross-sectional area of the wire.


The cross-sectional area of the wire is given by:

A=\pi r^2

where r is the radius of the wire. In this problem, r=\frac{d}{2}=\frac{2.0 mm}{2}=1.0 mm=0.001 m, so the cross-sectional area is

A=\pi (0.001 m)^2=3.14 \cdot 10^{-6} m^2


and the average current density is

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8 0
2 years ago
Read 2 more answers
You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t
kati45 [8]

Answer:

The  coefficient of kinetic friction  \mu_k =  0.724

Explanation:

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Generally from the work-energy theorem we have that  

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Here N  is the normal force acting on the truck which is mathematically represented as

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=>     \Delta KE =  0.5  *  m *  22.6^2

=>      \Delta KE =  255.38m

        255.38m =    m *  9.8  *  \mu_k *   36.0

=>     255.38  =    352.8  *  \mu_k

=>   \mu_k =  0.724

 

6 0
2 years ago
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