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spin [16.1K]
2 years ago
15

Reset the PhET simulation (using the button in the lower right) and set it up in the following manner: select Oscillate, select

No End, and use the parameters in parentheses by sliding the bars for Amplitude (1.00 cmcm), Frequency (1.40 HzHz ), Damping (none), and Tension (highest). Using the available Rulers, calculate the frequency of a photon that corresponds to the wavelength of the resulting wave. Assume the length with units (cmcm) of the ruler represents the real photon wavelength and that the speed of light is 3.00×108 m/s3.00×108 m/s.

Physics
1 answer:
lubasha [3.4K]2 years ago
5 0

Answer:

Check Explanation

Explanation:

This is a question that is as a result of an experimental procedure.

The Phet simulation is put on the settings given in the question;

- select Oscillate

- Select No End

- Use the parameters in parentheses by sliding the bars for Amplitude (1.00 cm), Frequency (1.40 Hz)

- Damping (none)

- Tension (highest)

I'll attach an interface of the Phet simulation to this solution.

Once all of these settings have been fixed, the simulation gives a wave pattern whose wavelength can be read from the ruler attached to the background of the simulation.

The wavelength is the distance from crest to crest or from trough to trough.

From the simulation example I have attached, the distance from crest to crest is from the green indicator on one crest to the green indicator on the next crest, that is about 5 to 5.1 cm

The velocity of a wave, v, is related to the frequency, f, and wavelength, λ of the wave through

v = fλ

For the photon, the velocity of the wave is the speed of light,

v = c = (3.00 × 10⁸) m/s

The wavelength computed from the simulation = λ = 5.1 cm = 0.051 m

c = fλ

frequency = (c/λ) = (3.00 × 10⁸) ÷ 0.051 = (5.88 × 10⁹) Hz

So, this step can be used to obtaim rhe required frequency of the photon, just follow these steps and use the calculation method too. You should be able to obtain the frequency of the photon in your experiment.

Hope this Helps!!!

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A bicyclist is riding at a tangential speed of 13.2 m/s around a circular track. The magnitude of the centripetal force is 377 N
MA_775_DIABLO [31]

Answer:

40m approximately

Explanation:

Given

Force =377N

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Velocity =13.2m/s

Required

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F=mv²/r

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r= mv²/F

Substitute

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4 0
2 years ago
A car is traveling with speed v0 when it begins to speed up at a rate of Δv every second. After t1 seconds, the car travels with
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Answer:

d = Δv(t2-t1)

Explanation:

Speed is defined as the change of displacement with respect to time. It is expressed as shown;

Speed = change in displacement/change in time

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d = ΔvΔt

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8 0
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The total energy of a 0.050 kg object travelling at 0.70 c is
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There is no exact match from the options.
4 0
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At a given instant the bottom A of the ladder has an acceleration aA = 4 f t/s2 and velocity vA = 6 f t/s, both acting to the le
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Answer:

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acceleration Ab=Aa +(Ab/a)+(Ab/a)t

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Solving equation 1

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Also from equation 2

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6 0
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