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spin [16.1K]
2 years ago
15

Reset the PhET simulation (using the button in the lower right) and set it up in the following manner: select Oscillate, select

No End, and use the parameters in parentheses by sliding the bars for Amplitude (1.00 cmcm), Frequency (1.40 HzHz ), Damping (none), and Tension (highest). Using the available Rulers, calculate the frequency of a photon that corresponds to the wavelength of the resulting wave. Assume the length with units (cmcm) of the ruler represents the real photon wavelength and that the speed of light is 3.00×108 m/s3.00×108 m/s.

Physics
1 answer:
lubasha [3.4K]2 years ago
5 0

Answer:

Check Explanation

Explanation:

This is a question that is as a result of an experimental procedure.

The Phet simulation is put on the settings given in the question;

- select Oscillate

- Select No End

- Use the parameters in parentheses by sliding the bars for Amplitude (1.00 cm), Frequency (1.40 Hz)

- Damping (none)

- Tension (highest)

I'll attach an interface of the Phet simulation to this solution.

Once all of these settings have been fixed, the simulation gives a wave pattern whose wavelength can be read from the ruler attached to the background of the simulation.

The wavelength is the distance from crest to crest or from trough to trough.

From the simulation example I have attached, the distance from crest to crest is from the green indicator on one crest to the green indicator on the next crest, that is about 5 to 5.1 cm

The velocity of a wave, v, is related to the frequency, f, and wavelength, λ of the wave through

v = fλ

For the photon, the velocity of the wave is the speed of light,

v = c = (3.00 × 10⁸) m/s

The wavelength computed from the simulation = λ = 5.1 cm = 0.051 m

c = fλ

frequency = (c/λ) = (3.00 × 10⁸) ÷ 0.051 = (5.88 × 10⁹) Hz

So, this step can be used to obtaim rhe required frequency of the photon, just follow these steps and use the calculation method too. You should be able to obtain the frequency of the photon in your experiment.

Hope this Helps!!!

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The trough of the sine curve used to represent a sound wave corresponds to
iren [92.7K]

Answer:

The correct answer is a rarefaction.

Explanation:

Sound waves are longitudinal waves that propagate in a medium, such as air. As the vibration continues, a series of successive condensations and rarefactions form and propagate from it. The pattern created in the air is something like a sinusoidal curve to represent a sound wave.

There are peaks in the sine wave at the points where the sound wave has condensations and valleys where it has rarefactions.

Have a nice day!

4 0
2 years ago
A 600-turn solenoid, 25 cm long, has a diameter of 2.5 cm. A 14-turn coil is wound tightly around the center of the solenoid. If
Delvig [45]

Answer:

The induced emf in the short coil during this time is 1.728 x 10⁻⁴ V

Explanation:

The magnetic field at the center of the solenoid is given by;

B = μ(N/L)I

Where;

μ is permeability of free space

N is the number of turn

L is the length of the solenoid

I is the current in the solenoid

The rate of change of the field is given by;

\frac{\delta B}{\delta t} = \frac{\mu N \frac{\delta i}{\delta t} }{L} \\\\\frac{\delta B}{\delta t} = \frac{4\pi *10^{-7} *600* \frac{5}{0.6} }{0.25}\\\\\frac{\delta B}{\delta t} =0.02514 \ T/s

The induced emf in the shorter coil is calculated as;

E = NA\frac{\delta B}{\delta t}

where;

N is the number of turns in the shorter coil

A is the area of the shorter coil

Area of the shorter coil = πr²

The radius of the coil = 2.5cm / 2 = 1.25 cm = 0.0125 m

Area of the shorter coil = πr² = π(0.0125)² = 0.000491 m²

E = NA\frac{\delta B}{\delta t}

E = 14 x 0.000491 x 0.02514

E = 1.728 x 10⁻⁴ V

Therefore, the induced emf in the short coil during this time is 1.728 x 10⁻⁴ V

8 0
2 years ago
calculate the work done to stretch an elastic string by 40cm if a force of 10N produces an extension of 4cm in it?
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100N is how much work is needed 
4 0
2 years ago
A pitcher delivers a fast ball with a velocity of 43 m/s to the south. the batter hits the ball and gives it a velocity of 51 m/
hoa [83]
Assuming north as positive direction, the initial and final velocities of the ball are:
v_i=-43 m/s (with negative sign since it is due south)
v_f=+51 m/s
the time taken is t=1.0 ms=0.001 s, so the average acceleration of the ball is given by
a= \frac{v_f-v_i}{t}= \frac{51 m/s-(-43 m/s)}{0.001 s}=9.4 \cdot 10^4 m/s^2
And the positive sign tells us the direction of the acceleration is north.
4 0
1 year ago
Danielle is doing some DIY. She uses a 1.2kW electric saw for 20 minutes and then a 1000W electric sander for half an hour. Whic
mixas84 [53]

Answer:

1.2kw because it is kilowatt

4 0
1 year ago
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