Ask question

Ask question

All categories

2 years ago

11

At the town carnival Darren rode the ferris wheel seven times and the bumper cars three times. if each ride cost five tickets. a

nd each ticket cost $0.50, how much money did he spend ?

1 answer:

stira [4]2 years ago

3 0

Answer:

$10.5

Step-by-step explanation:

You might be interested in

The rabbit population on a small island is observed to be given by the function P(t) = 130t − 0.3t^4 + 1100 where t is the time

Montano1993 [528]

The maximum occurs when the derivative of the function is equal to zero.
$P(t)=-0.3t^{4}+130t+1100 \\ P'(t)=-1.2t^{3}+130 \\ 0=-1.2t^{3}+130 \\ 1.2t^{3}=130 \\ t^{3}= \frac{325}{3} \\ t=4.76702$
Then evaluate the function for that time to find the maximum population.
$P(t)=-0.3t^{4}+130t \\ P(4.76702)=-0.3*4.76702^{4}+130*4.76702+1100 \\ P(4.76702)=1564.79201$
Depending on the teacher, the "correct" answer will either be the exact decimal answer or the greatest integer of that value since you cannot have part of a rabbit.

7 0

2 years ago

If a cube has an edge of 2 feet. The edge is increasing at the rate of 6 feet per minute. How would i express the volume of the

photoshop1234 [79]

Answer:

v(m) = 8 + 48m+ 180m² +216m³

Step-by-step explanation:

Let's first of all represent the edge of the the cube as a function of minutes.

Initially the egde= 2feet

As times elapsed , it increases at the rate of 6 feet per min, that is, for every minute ,there is a 6 feet increase.

Let the the egde be x

X = 2 + 6(m)

Where m represent the minutes elapsed.

So we Al know that the volume of an edge = edge³

but egde = x

V(m) = x³

but x= 2+6(m)

V(m) = (2+6m)³

v(m) = 8 + 48m+ 180m² +216m³

8 0

1 year ago

The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev

Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 30.05 inches

$\sigma$ = standard deviation = 0.2 inches

n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches) = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } }$ ) = P(Z < 3) = 0.99865

P(X bar <= 30.25) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } }$ ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches) = 0.99865 - 0.97725

= 0.0214

7 0

2 years ago

What is the 185th digit in the following pattern 12345678910111213141516...?

Natalka [10]

1-9 = 9 digits
10-99 = 180 digits
So if we continue the pattern to 99, there are 189 digits, and the last 5 digits would be 79899. Counting backwards: 189th = 9, 188th = 9, 187th = 8, 186th = 9, 185th = 7.

The 185th digit is 7.

4 0

2 years ago

Town Hall is located 4.3 miles directly east of the middle school. The fire station is located 1.7 miles directly north of Town

Maksim231197 [3]

Answer:

2.1 miles

Step-by-step explanation:

you can see a drawing of the situation in the attached picture (you need to draw all the places mentioned and the distance between them),

this way we can form a right triangle between the school and the hospital with measures of sides: 1.7 and 1.2 miles

and the green line is the straight line between the school and the hospital, so you need pythagoras to find the value:

$\sqrt{1.7^2+1.2^2}\\=\sqrt{2.89+1.44}\\=\sqrt{4.33} \\ =2.081$

rounding to the nearest tenth:

2.1 miles

4 0

2 years ago