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1 year ago

11

At the town carnival Darren rode the ferris wheel seven times and the bumper cars three times. if each ride cost five tickets. a

nd each ticket cost $0.50, how much money did he spend ?

1 answer:

stira [4]1 year ago

3 0

Answer:

$10.5

Step-by-step explanation:

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What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

uysha [10]

Answer:

The perimeter of the trapezoid is $38.25\ units$

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

so

In this problem

$P=QR+RS+ST+QT$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$Q(8, 8), R(14, 16), S(20, 16),T(22, 8)$

step 1

Find the distance QR

$Q(8, 8), R(14, 16)$

substitute the values in the formula

$d=\sqrt{(16-8)^{2}+(14-8)^{2}}$

$d=\sqrt{(8)^{2}+(6)^{2}}$

$d=\sqrt{100}$

$QR=10\ units$

step 2

Find the distance RS

$R(14, 16), S(20, 16)$

substitute the values in the formula

$d=\sqrt{(16-16)^{2}+(20-14)^{2}}$

$d=\sqrt{(0)^{2}+(6)^{2}}$

$d=\sqrt{36}$

$RS=6\ units$

step 3

Find the distance ST

$S(20, 16),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-16)^{2}+(22-20)^{2}}$

$d=\sqrt{(-8)^{2}+(2)^{2}}$

$d=\sqrt{68}$

$ST=8.25\ units$

step 4

Find the distance QT

$Q(8, 8),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-8)^{2}+(22-8)^{2}}$

$d=\sqrt{(0)^{2}+(14)^{2}}$

$d=\sqrt{196}$

$QT=14\ units$

step 5

Find the perimeter

$P=10+6+8.25+14=38.25\ units$

6 0

2 years ago

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Which congruence theorem can be used to prove △BDA ≅ △DBC? Triangles B D A and D B C share side D B. Angles C B D and A D B are

Tomtit [17]

Answer:

A. Hypotenuse-leg (HL) congruence.

HL, when you have 2 right triangles and their hypotenuses are congruent you are able to say HL

Step-by-step explanation:

We know that the hypotenuse-leg theorem states that if the hypotenuse and one leg of a right triangle are congruent to hypotenuse and corresponding leg of another right triangle, then the triangles are congruent.

hypotenuse(AB) of △BDA equals to hypotenuse (CD) of △DBC.

BDA and DBC share a common side DB.

Using Pythagorean theorem we will get,

$CD^{2}=DB^{2}+BC^{2}...(1) \\\\AB^{2}=DB^{2}+AD^{2}...(2)$

We have been given that CD=AB, Upon using this information we will get,

$DB^{2}+BC^{2}=DB^{2}+AD^{2}$

Upon subtracting $DB^{2}$ from both sides of our equation we will get,

$BC^{2}=AD^{2}\\\\BC=AD$

<h3>Therefore, by HL congruence △BDA ≅ △DBC.</h3>

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1 year ago

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The time, in minutes, it took each of 11 students to complete a puzzle was recorded and is shown in the following list

bija089 [108]

Answer:

30, 31, 32, 35, and 38

Step-by-step explanation:

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2 years ago

3. 24% of weight of an explosive mixture is saltpetre. Find the weight of a sample in which the other ingredients

Art [367]

Answer:

76% of X= 9.12. X= 12 gram. Therefore weight of the sample is 12 gram.

Step-by-step explanation:

i hope it's help you

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1 year ago

Lois has a balance of $970 on a credit card with an APR of 24.2%, compounded monthly. About how much will she save in interest o

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<span>$152.51
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1 year ago

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