Question

A crate is lifted vertically 1.5 m and then held at rest. The crate has weight 100 N (i.e., it is reese (enr647) – HS OnRamps 04: Intro to Work and Energy – mcdaniel – (34472020) 2 supported by an upward force of 100 N). How much work is being done to hold the crate 1.5 m above the ground in this way?

Answer 1

Answer:150Joules

Explanation:

Work is said to be done if a force is applied to cause a body to move through a distance.

Work done = Force × distance

Given force = 100N

Distance = 1.5m

Work done = 100 × 1.5

Work done = 150Joules.

Answer 2

Answer:

W = 0 J

Explanation:

It is given that,

Weight of the crate, W = 100 N

Distance moved by the crate, d = 1.5 m

Let W is the work done to hold the crate 1.5 m above the ground in this way. It is given by the product of force and the displacement. Its formula is given by :

$W=F\times d\times cos\theta$

Here, $\theta=90^{\circ}$ as it is lifted vertically

$W=100\ N\times 1.5\ m\ cos(90)$      

W = 0

So, the work done to hold the crate is 0. Hence, this is the required solution.