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2 years ago

4. Discuss how well Democritus' ideas about atoms have withstood the test of time.

Chemistry

2 answers:

love history [14]2 years ago

8 0

Answer:

Democritus thought that atoms were the smallest particle and could not be divided any more. The word 'atomos' which atom is derived from, means indivisible. we now know that atoms are made of sub-atomic particles, which are made of quarks (what sort of name is that), and these quarks are made of leptons and gluons.

lol.. my account got deleted so imma yeet some points back... Mark me brainliest please... not the other account..

Alex Ar [27]2 years ago

6 0

Answer:

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What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon

Ulleksa [173]

Answer:

Theoretical yield = 31.8 g

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For $Al_2O_3$

Mass of $Al_2O_3$ = 60.0 g

Molar mass of $Al_2O_3$ = 101.96128 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{60.0\ g}{101.96128\ g/mol}$

$Moles_{Al_2O_3}= 0.5885\ mol$

Given: For $C$

Given mass = 30.0 g

Molar mass of $C$ = 12.0107 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{30.0\ g}{12.0107\ g/mol}$

$Moles_{C}= 2.4978\ mol$

According to the given reaction:

$Al_2O_3+3C\rightarrow 2Al+3CO$

1 mole of aluminium oxide react with 3 moles of carbon

0.5885 mole of aluminium oxide react with $3\times 0.5885$ moles of carbon

Moles of carbon = 1.7655 moles

Available moles of carbon = 2.4978 moles

Limiting reagent is the one which is present in small amount. Thus, aluminium oxide is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of aluminium oxide on reaction forms 2 moles of aluminium.

0.5885 mole of aluminium oxide on reaction forms $2\times 0.5885$ moles of aluminium.

Moles of aluminium = 1.177 moles

Molar mass of aluminium = 26.981539 g/mol

Mass of sodium sulfate = Moles × Molar mass = 1.177 × 26.981539 g = 31.8 g

<u> Theoretical yield = 31.8 g</u>

3 0

2 years ago

How many moles of AgNO3 must react to form 0.854 mol Ag?

kipiarov [429]

The answer:
<span>The equation of its dissolution in water is: AgNO3 → Ag + (aq) + NO3- (aq)

and </span>AgNO3 → Ag + (aq) + NO3- (aq)
1 mol 1mol 1mol
? -------- 0.854mo
so for finding the value, it is sufficients to complute 1 x 0.854 mol =0.854 mol
so, 0.854 mol is required for the reaction to form 0.854 mol of Ag

5 0

2 years ago

Read 2 more answers

Calculate the freezing point of a 0.100 m aqueous solution of k2so4, taking interionic attractions into consideration by using t

Leokris [45]

Ionic salt dissociate completely in water particularly in water at low concentration.
The molal freezing point of depression constant for water is 1.85kg/k/mol
therefore depression of freezing point =1.853 x 0.100 x 2.32=0.429 degrees celsius
hence solute freeze at - 0.429 degree celsius

3 0

2 years ago

Which of the samples described below contains the FEWEST atoms? No calculation is needed to answer this question.

Monica [59]

Hello!

To do this, use the molar mass. This is how much a mole of an atom weighs. A mole is 6.02214076×10²³ atoms.

Molar masses of:

Se: 78.96 g/mol

Cu: 63.546 g/mol

Ba: 137.327 g/mol

Now, the element with the highest molar mass will have the fewest atoms. This is because the element weighs more, so therefore for the same amount of mass, there will be less of the element needed to reach that mass.

Therefore, 10g of Ba would have the fewest number of atoms.

Hope this helps!

6 0

2 years ago

A graduated cylinder holds 100 mL of water. A lead weight is dropped into the cylinder bringing the new volume up to 450 mL. If

dolphi86 [110]

11.43g/mL

Explanation:

Given parameters:

Volume of water in the graduated cylinder = 100mL

Volume of water + lead weight = 450mL

Mass of lead weight = 4000g

Unknown:

Density of the lead weight = ?

Solution:

Density is the mass per unit volume of a body.

Density = $\frac{mass}{volume}$

Volume of the lead weight = volume of water displaced

Volume of lead weight = 450 - 100 = 350mL

Density = $\frac{4000}{350}$ = 11.43g/mL

learn more:

Density brainly.com/question/2690299

#learnwithBrainly

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2 years ago