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sweet [91]
2 years ago
13

When a small piece of white marble rock is carefully placed in a beaker of hydrochloric acid, bubbles form on the surface of the

rock and rise to the top of the liquid. Which conclusion best fits this observation?
A.The rock heated the acid until it began to boil.
B.The rock dissolved in the acid by breaking into its smallest pieces.
C.The rock was changed by the acid into its gaseous form.
D.The rock reacted with the acid and made a new gaseous substance.

Chemistry
2 answers:
MrRa [10]2 years ago
8 0
Hi there!!

The answer you are looking for is....


D. <span>The rock reacted with the acid and made a new gaseous substance.


Hope I helped you!</span>

borishaifa [10]2 years ago
7 0
Hello there,

The rock reacted with the acid and made a new gaseous substance

Hope this helps.

~Jurgen :)
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How many molecules of glucose are in 1 l of a 100 mm glucose solution?
Karolina [17]

Answer is: 6.022·10²² molecules of glucose.

c(glucose) = 100 mM.

c(glucose) = 100 · 10⁻³ mol/L.

c(glucose) = 0.1 mol/L; concentration of glucose solution.

V(glucose) = 1 L; volume of glucose solution.

n(glucose) = c(glucose) · V(glucose).

n(glucose) = 0.1 mol/L · 1 L.

n(glucose) = 0.1 mol; amount of substance.

N(glucose) = n(glucose) · Na (Avogadro constant).

N(glucose) = 0.1 mol · 6.022·10²³ 1/mol.

N(glucose) = 6.022·10²².

6 0
2 years ago
The terms motif (fold) and domain describe levels of protein organization more complicated than primary or secondary structure.
posledela

Answer:

Each specific property of motif and domain is explained.

Explanation:

Domain;

  • May retain a 3D structure when separated from rest of the protein.          
  • Unit of tertiary structure because alpha helix and beta sheets are units of secondary structure.
  • Stable globular units like pyruvate kinase
  • May be distinct functional units in a protein

Motif;

  • Repetetive supersecondary structure because they contain cluster of secondary structure.
  • Beta Alpha Beta unit is an example of motif
  • Clusters of secondary structure

Both Motif and Domain;

  • Stabilized by hydrophobic interactions like hydrogen bonding stabilize the both.
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8 0
2 years ago
A collection of coins contains 14 pennies, 16 dimes, and 7 quarters. What is the percentage of pennies in the collection?A colle
marin [14]

Answer:

=37.83783784

Explanation:

Find the total sum of all coins,

which is 37, take the number of pennies and the total of all coins put in parenthesis( 14/37) like so and than * times them by 100

you equation should look like this

(14/37)* 100= and than the answer shown above should be the one you received. I have checked this with multiple calculators, it should be accurate.  

8 0
2 years ago
Read 2 more answers
The reaction of 0.779 g K with O2 forms 1.417 g potassium superoxide, a substance used in self-contained breathing devices. Dete
zhannawk [14.2K]
First we need to find the number of moles of both K and O reacted
K - 0.779 g / 39 g/mol
  = 0.02 mol
the mass of O₂ reacted = 1.417 g - 0.779 g = 0.638 g
O₂ moles = 0.638 g / 32 g/mol
               = 0.02 mol 
the number of both K and O₂ moles reacted are equal 
therefore stoichiometry of K to O₂ reacted are 1:1 
then the formula of potassium superoxide is KO₂
3 0
2 years ago
If 10.0 grams of NaHCO3 is added to 10.0 g of HCl, determine the efficiency of baking soda as an antacid if 6.73 g of NaCl was p
Lapatulllka [165]

Answer:

percentage yield of NaCl = 96.64%

Explanation:

The reaction was between NaHCO3 and HCl .The chemical equation can be represented below:

NaHCO3 + HCl → NaCl + H2O + CO2 . The balance equation is

NaHCO3 + HCl → NaCl + H2O + CO2

The question ask us to calculate the percentage yield of NaCl.

The efficiency of NaHCO3 as an antacid , the limiting reactant is NaHCO3

as

1 mole of NaHCO3 produces 1 mole of NaCl

Therefore,

molar mass of NaHCO3 = 23 +1 + 12 + 48 = 84 g

molar mass of NaCl = 23 + 35.5 = 58.5 g

1 mole of NaHCO3 = 84 g

1 mole of NaCl  = 58.5 g

since 84 g of NaHCO3 produces 58.5 g of NaCl

10 g of NaHCO3 will produce ? grams of NaCl

cross multiply

Theoretical yield of NaCl = (10 × 58.5)/84

Theoretical yield of NaCl = 585/84

Theoretical yield of NaCl  = 6.9642857143 g

percentage yield of NaCl = actual yield/theoretical yield × 100

percentage yield of NaCl = 6.73/6.9642857143 × 100

percentage yield of NaCl = 673/6.9642857143

percentage yield of NaCl = 96.635897436%

percentage yield of NaCl = 96.64%

3 0
2 years ago
Read 2 more answers
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