Question

Khalid loses 1/3rd of his money in the first game, 3.5ths of the remainder in the second and 4/7ths of the rest in the third. Thus he is left with . . . . .. ths of his money:
(a) 4/15
(b) 4/35
(c) 14/35
(d) 24/35

Answer 1

Answer: 4/35

Step-by-step explanation:

Let the original money be x , then

in the first game Khalid lost 1/3 of x

The remainder will be x - x/3 = 2x/3

3/5 of the remainder in the second game implies

3/5 X 2x/3 = 2x/5

The remainder now becomes 2x/3 - 2x/ 5 = 4x/15

4/7 of the rest implies 4/7 X 4x/15 = 16x/105

The rest will therefore be 4x/ 15 - 16x/105 = 4x/35