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Karolina [17]
2 years ago
9

Write the quadratic equation whose roots are six and -2 and who’s leading coefficient is 3 use the letter X to represent the var

iable
Mathematics
1 answer:
Artist 52 [7]2 years ago
6 0

Answer:

3X^{2} - 12X - 36 = 0

Step-by-step explanation:

6 and - 2 are the only two solutions to the required quadratic equation.

So, if the variable is represented by X then (X - 6) and (X + 2) will be the only two factors of the polynomial function.

Therefore, the equation is  

(X - 6)(X + 2) = 0

⇒ X^{2} - 4X - 12 = 0

If the leading coefficient of the equation is 3 then we can write the equation as 3X^{2} - 12X - 36 = 0 (Answer)

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galina1969 [7]
Get rid of cos2x by dividing both the values. So Sin2x/cos2x +3cos2x/cos2x.
Tan2x = 3
2x = -71.5 so x is -35.6
Use the quadrant method and add 360 twho the two values tou get.
7 0
2 years ago
Match each pair of points to the equation of the line that is parallel to the line passing through the points.
Paraphin [41]

we know that

If two lines are parallel, then, their slopes are equal.

The formula to calculate the slope between two points is equal to


m=\frac{y2-y1}{x2-x1}


we will proceed to calculate the slope in each case, to determine the solution of the problem

<u>Case A)</u> Point B(5,2)\ C(7,-5)

Find the slope BC

Substitute the values in the formula

m=\frac{-5-2}{7-5}


m=\frac{-7}{2}


m=-3.5


so

The equation y=-3.5x-15 is parallel to the line passing through the points B(5,2)\ C(7,-5)

therefore

<u>the answer Part A) is</u>

B(5,2)\ C(7,-5) ------> y=-3.5x-15

<u>Case B)</u> Point D(11,6)\ E(5,9)

Find the slope DE

Substitute the values in the formula

m=\frac{9-6}{5-11}


m=\frac{3}{-6}


m=-0.5


so

The equation y=-0.5x-3 is parallel to the line passing through the points D(11,6)\ E(5,9)

therefore

<u>the answer Part B) is</u>

D(11,6)\ E(5,9) ------> y=-0.5x-3

<u>Case C)</u> Point F(-7,12)\ G(3,-8)

Find the slope FG

Substitute the values in the formula

m=\frac{-8-12}{3+7}  

m=\frac{-20}{10}


m=-2


so

Any linear equation with slope m=-2 will be parallel to the line passing through the points F(-7,12)\ G(3,-8)

<u>Case D)</u> Point H(4,4)\ I(8,9)

Find the slope HI

Substitute the values in the formula

m=\frac{9-4}{8-4}


m=\frac{5}{4}


m=1.25


so

The equation y=1.25x+4 is parallel to the line passing through the points H(4,4)\ I(8,9)

therefore

<u>the answer Part D) is</u>

H(4,4)\ I(8,9) ------> y=1.25x+4

<u>Case E)</u> Point J(7,2)\ K(-9,8)

Find the slope JK

Substitute the values in the formula

m=\frac{8-2}{-9-7}


m=\frac{6}{-16}


m=-0.375


so

Any linear equation with slope m=-0.375 will be parallel to the line passing through the points  J(7,2)\ K(-9,8)

<u>Case F)</u> Point L(5,-7)\ M(4,-12)

Find the slope LM

Substitute the values in the formula

m=\frac{-12+7}{4-5}


m=\frac{-5}{-1}


m=5


so

The equation y=5x+19 is parallel to the line passing through the points L(5,-7)\ M(4,-12)

therefore

<u>the answer Part F) is</u>

L(5,-7)\ M(4,-12) ------>  y=5x+19




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CD = \sqrt{(a-0)^{2}+ (b-b)^{2}  }

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Answer:

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