answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tatiyna
1 year ago
10

Match each pair of points to the equation of the line that is parallel to the line passing through the points.

Mathematics
2 answers:
Paraphin [41]1 year ago
8 0

we know that

If two lines are parallel, then, their slopes are equal.

The formula to calculate the slope between two points is equal to


m=\frac{y2-y1}{x2-x1}


we will proceed to calculate the slope in each case, to determine the solution of the problem

<u>Case A)</u> Point B(5,2)\ C(7,-5)

Find the slope BC

Substitute the values in the formula

m=\frac{-5-2}{7-5}


m=\frac{-7}{2}


m=-3.5


so

The equation y=-3.5x-15 is parallel to the line passing through the points B(5,2)\ C(7,-5)

therefore

<u>the answer Part A) is</u>

B(5,2)\ C(7,-5) ------> y=-3.5x-15

<u>Case B)</u> Point D(11,6)\ E(5,9)

Find the slope DE

Substitute the values in the formula

m=\frac{9-6}{5-11}


m=\frac{3}{-6}


m=-0.5


so

The equation y=-0.5x-3 is parallel to the line passing through the points D(11,6)\ E(5,9)

therefore

<u>the answer Part B) is</u>

D(11,6)\ E(5,9) ------> y=-0.5x-3

<u>Case C)</u> Point F(-7,12)\ G(3,-8)

Find the slope FG

Substitute the values in the formula

m=\frac{-8-12}{3+7}  

m=\frac{-20}{10}


m=-2


so

Any linear equation with slope m=-2 will be parallel to the line passing through the points F(-7,12)\ G(3,-8)

<u>Case D)</u> Point H(4,4)\ I(8,9)

Find the slope HI

Substitute the values in the formula

m=\frac{9-4}{8-4}


m=\frac{5}{4}


m=1.25


so

The equation y=1.25x+4 is parallel to the line passing through the points H(4,4)\ I(8,9)

therefore

<u>the answer Part D) is</u>

H(4,4)\ I(8,9) ------> y=1.25x+4

<u>Case E)</u> Point J(7,2)\ K(-9,8)

Find the slope JK

Substitute the values in the formula

m=\frac{8-2}{-9-7}


m=\frac{6}{-16}


m=-0.375


so

Any linear equation with slope m=-0.375 will be parallel to the line passing through the points  J(7,2)\ K(-9,8)

<u>Case F)</u> Point L(5,-7)\ M(4,-12)

Find the slope LM

Substitute the values in the formula

m=\frac{-12+7}{4-5}


m=\frac{-5}{-1}


m=5


so

The equation y=5x+19 is parallel to the line passing through the points L(5,-7)\ M(4,-12)

therefore

<u>the answer Part F) is</u>

L(5,-7)\ M(4,-12) ------>  y=5x+19




lord [1]1 year ago
5 0

Answer:

Step-by-step explanation:

Plato Answer simplified:

(4,4) (8,9) - y=1.25x+4

(5,2) (7,-5) - y=-3.5x-15

(11,6) (5,9) - y=-0.5x-3

(5,-7) (4,-12) - y=5x+19

Example of how to do it in your head if you have multiple choice:

Note the order, you start from right to left with the coordinates...

(4,4) (8,9) - y=1.25x+4

9   -    4     The Y's         5

8   -    4     The X's         4

                                      _

                                    1.25x

(5,2) (7,-5) - y=-3.5x-15

-5   -    2     The Y's        -7

7   -    5     The X's         2

                                       _

                                    -3.5x

(11,6) (5,9) - y=-0.5x-3

9   -    6     The Y's         3

5   -    11     The X's        -6

                                       _

                                    -0.5x

(5,-7) (4,-12) - y=5x+19

-12   -    -7     The Y's        -5

 4   -     5     The X's         -1

                                         _

                                         5x

You might be interested in
Find the eccentricity, b. identify the conic, c. give an equation of the directrix, and d. sketch the conic.
densk [106]

Answer:

a) 10/3  

b) hyperbola

c) x = ± 6/5

Step-by-step explanation:

a) A conic section with a focus at the origin, a directrix of x = ±p where p is a positive real number and positive eccentricity (e) has a polar equation:

r=\frac{ep}{1\pm e*cos\theta}

Given the conic equation: r=\frac{12}{3-10cos\theta}

We have to make it to be in the form r=\frac{ep}{1\pm e*cos\theta}:

r=\frac{12}{3-10cos\theta}\\\\multiply\ both\ sides\ by\ \frac{1}{3} \\\\r=\frac{12*\frac{1}{3}}{(3-10cos\theta)*\frac{1}{3}}\\\\r=\frac{12*\frac{1}{3}}{3*\frac{1}{3}-10cos\theta*\frac{1}{3}}\\\\r=\frac{4}{1-\frac{10}{3}cos\theta } \\\\r=\frac{\frac{10}{3}(\frac{6}{5} ) }{1-\frac{10}{3}cos\theta }

Comparing with  r=\frac{ep}{1\pm e*cos\theta}

e = 10/3 = 3.3333, p = 6/5

b) since the eccentricity = 3.33 > 1, it is a hyperbola

c) The equation of the directrix is x = ±p = ± 6/5

6 0
2 years ago
Which of the following completes the proof? Triangles ABC and EDC are formed from segments BD and AC, in which point C is betwee
kotykmax [81]

Answer: ∠ACB ≅ ∠E'C'D'; translate point D' to point B

Step-by-step explanation:

That is just my best guess.

3 0
2 years ago
Read 2 more answers
A flat circular plate has the shape of the region x squared plus y squared less than or equals 1x2+y2≤1. the​ plate, including t
vredina [299]

You're looking for the extreme values of x^2+3y^2+13x subject to the constraint x^2+y^2\le1.

The target function has partial derivatives (set equal to 0)

\dfrac{\partial(x^2+3y^2+13x)}{\partial x}=2x+13=0\implies x=-\dfrac{13}2

\dfrac{\partial(x^2+3y^2+13x)}{\partial y}=6y=0\implies y=0

so there is only one critical point at \left(-\dfrac{13}2,0\right). But this point does not fall in the region x^2+y^2\le1. There are no extreme values in the region of interest, so we check the boundary.

Parameterize the boundary of x^2+y^2\le1 by

x=\cos u

y=\sin u

with 0\le u. Then t(x,y) can be considered a function of u alone:

t(x,y)=t(\cos u,\sin u)=T(u)

T(u)=\cos^2u+3\sin^2u+13\cos u

T(u)=3+13\cos u-2\cos^2u

T(u) has critical points where T'(u)=0:

T'(u)=-13\sin u+4\sin u\cos u=\sin u(4\cos u-13)=0

(1)\quad\sin u=0\implies u=0,u=\pi

(2)\quad4\cos u-13=0\implies\cos u=\dfrac{13}4

but |\cos u|\le1 for all u, so this case yields nothing important.

At these critical points, we have temperatures of

T(0)=14

T(\pi)=-12

so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.

4 0
1 year ago
Choose the option that best completes the statement below. In finding the number of permutations for a given number of items, __
vodomira [7]
Let’s look at the permutations of the letters “ABC.” We can write the letters in any of the following ways:
ABC
ACB
BAC
BCA
CBA
CAB
Since there are 3 choices for the first spot, two for the next and 1 for the last we end up with (3)(2)(1) = 6 permutations. Using the symbolism of permutations we have: 3 P_{3}=(3)(2)(1)=6. Note that the first 3 should also be small and low like the second one but I couldn’t get that to look right.

Now let’s see how this changes if the letters are AAB. Since the two As are identical, we end up with fewer permutations.
AAB
ABA
BAA
To make the point a bit better let’s think of one A are regular and one as bold A.
A
BA and ABA look different now because we used bold for one of the As but if we don’t do this we see that these are actual the same. If they represented a word they would be the same exact word.

So in this case the formula would be \frac{3 P_{3} }{2!}= \frac{(3)(2)(1)}{(2)(1)}= \frac{6}{2}=3. We use 2! In the denominator because there are 2 repeating letters. If there were three we would use 3!


Hopefully, this is enough to let you see that the answer is A. The number of permutations is limited by the number of items that are identical.



7 0
2 years ago
The box plot shows the number of years during which 24 colleges have participated in a local college fair: A boxplot is titled Y
Anna007 [38]

Answer:

its is actually 4

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Other questions:
  • An audience of 450 people is seated in an auditorium. Each row contains the same number of seats and each seat in the auditorium
    15·2 answers
  • Helene is finding the sum (9 + 10i) + (–8 + 11i). She rewrites the sum as (–8 + 11)i + (9 + 10)i. Which statement explains the p
    11·2 answers
  • The heights of 1000 students are approximately normally distributed with a mean of 174.5 centimeters and a standard deviation of
    10·1 answer
  • Jamie just bought two boxes.The first box is square with each side measuring 10 units and is 4 units high.The second box is rect
    15·1 answer
  • The figure below shows a triangular wooden frame ABC. The side AD of the frame has rotted and needs to be replaced: What is the
    12·2 answers
  • A student is raising money for cancer research. A local business agrees to donate an additional 25% of what the student raises,
    7·1 answer
  • The $120 repair bill included $36 for parts and rest for labor. What percent of the bill was for labor?​
    7·1 answer
  • Segment GI is congruent to Segment JL and Segment GH is congruent to Segment KL. I have to prove Segment HI is congruent to Segm
    10·1 answer
  • Maple street is 3 times as long as pine street. how long is pine street?
    9·2 answers
  • Write the equivalent fraction, the reduced fraction, and the decimal equivalent for 45%. Jenny solved this problem and her work
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!