Answer:
Step-by-step explanation:
1 ) Given that

For a non homogeneous part
, we assume the particular solution is

2 ) Given that

For a non homogeneous part
, we assume the particular solution is

3 ) Given that
y′′ + 4y′ + 20y = −3sin(2x)
For a non homogeneous part −3sin(2x) , we assume the particular solution is

4 ) Given that
y′′ − 2y′ − 15y = 3xcos(2x)
For a non homogeneous part 3xcos(2x) , we assume the particular solution is

Answer:
- 880 lbs of all-beef hot dogs
- 2000 lbs of regular hot dogs
- maximum profit is $3320
Step-by-step explanation:
We can let x and y represent the number of pounds of all-beef and regular hot dogs produced, respectively. Then the problem constraints are ...
- .75x + 0.18y ≤ 1020 . . . . . . limit on beef supply
- .30y ≤ 600 . . . . . . . . . . . . . limit on pork supply
- .2x + .2y ≥ 500 . . . . . . . . . . limit on spice supply
And the objective is to maximize
p = 1.50x + 1.00y
The graph shows the constraints, and that the profit is maximized at the point (x, y) = (880, 2000).
2000 pounds of regular and 880 pounds of all-beef hot dogs should be produced. The associated maximum profit is $3320.
Answer: The required expression would be
.
Step-by-step explanation:
Since we have given that
Let the regular price of an item be 'p' dollars.
Discount % = 20%
So, Amount of discount would be

So, the expression represents the sale price would be

Hence, the required expression would be
.
Answer:
m=24
Explanation: 120/5=24 just caculate it.
The answer would have to be 11.00 if im correct.