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Basile [38]
2 years ago
8

Which expression is equivalent to square root of -80

Mathematics
2 answers:
Yuki888 [10]2 years ago
7 0

Answer:

The equivalent expression is (4\sqrt{5})i

Step-by-step explanation:

Given the expression \sqrt{-80} we can use prime factorization and a property of imaginary numbers to obtain an equivalent expression.

Let's start applying prime factorization over 80

80=(2).(40)=(2).(2).(20)=(2).(2).(2).(10)=(2).(2).(2).(2).(5)=(2^{4}).(5)

The other property is i^{2}=-1 (This is a property of imaginary numbers).

We can write -80 as

-80=(2^{4}).(5).i^{2}

Now we apply square root to the expression ⇒

\sqrt{(2^{4}).(5).i^{2}}=(4\sqrt{5})i

Law Incorporation [45]2 years ago
5 0
Sqrt(-80) = 8.94427191i
Hope it helped :d
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madreJ [45]
So we are given a system:
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10y-15z=30\\
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-25z=0\text{ then}z=0.
We find the value of y by using any of the other equations like this:
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8 0
1 year ago
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In the next step, we cancel out 3x

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7 0
2 years ago
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the graph of f(x) shown below has the same shape as the graph of g(x)=x^2 but is shifted down 5 units and to the left 4 units (t
schepotkina [342]

Answer:

Option C

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A function g(x) = x² has been given as the parent function.

This function then shifted 5 units down.

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Further this graph has been shifted 4 units to the left then the function will become

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Therefore, option C is the answer.

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The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 30.05 inches

           \sigma   = standard deviation = 0.2 inches

             n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches)  = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z < 3) = 0.99865

 P(X bar <= 30.25) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches)  = 0.99865 - 0.97725

                                                                                       = 0.0214

                                       

7 0
2 years ago
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Alika [10]
<h3>There are 96 roses altogether</h3>

<em><u>Solution:</u></em>

Let "x" be the number of roses

From given,

<em><u>1/4 of the roses are red</u></em>

Red\ roses = \frac{1}{4} \times x\\\\Red\ roses = \frac{x}{4}

<em><u>1/3 of the remainder are yellow</u></em>

Remaining = x - \frac{x}{4}\\\\Remaining = \frac{3x}{4}

Therefore,

Yellow\ roses = \frac{1}{3} \times \frac{3x}{4}\\\\Yellow\ roses = \frac{x}{4}

<em><u>Rest are pink</u></em>

Remaining = \frac{3x}{4} - \frac{x}{4}\\\\Remaining = \frac{2x}{4}\\\\Remaining = \frac{x}{2}

Therefore,

Pink\ Roses = \frac{x}{2}

There are 24 more pink roses than red roses

Therefore,

Number of pink roses = 24 + red roses

\frac{x}{2} = 24 + \frac{x}{4}\\\\\frac{x}{2} -  \frac{x}{4} = 24\\\\\frac{x}{4} = 24\\\\x = 24 \times 4\\\\x = 96

Thus there are 96 roses altogether

7 0
2 years ago
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