I'm not sure exactly which type you are meaning since there are four types of expansions, but depending on which specific type here are your answers! :)
Answer:
Option (D)
Step-by-step explanation:
Given polynomial is,
2x³ - 3x² - 3x + 2
If (x - 2) is the factor of the given polynomial,
By synthetic division we can get the other factor.
2 | 2 -3 -3 2
<u> 4 2 -2 </u>
2 1 -1 0
Therefore, other factor of the given polynomial is (2x² + x - 1)
Now (2x² + x - 1) = 2x² + 2x - x - 1
= 2x(x + 1) -1(x + 1)
= (2x - 1)(x + 1)
Therefore, factors of the given polynomial other than (x - 2) are (2x - 1) and (x + 1)
Option (D) will be the answer.
Hello.<span><span> </span><span>
<span><span>
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Let 2003 be the zero year; then 2005 is the three year, and 2008 the 5 year.
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P = ab^x
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P(3) = ab^3 = 800000
P(0) = ab^0 = 900000
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a = 900000
Solve for "b"::
b^3 = 8/9
b = 2/cbrt(9)
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Equation::
P(x) = 900000^x
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Ans: P(5) = 900000
Have a nice day</span></span></span></span>
There were 340,000 cattle placed on feed
How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?
Given the fraction of total cattle for 700 - 799 pounds is 2/5
Let x be the number of cattle between 700 - 799 pounds
We make a proportion using the fraction

Cross multiply it and solve for x
340000* 2 = 5x
680000 = 5x
Divide by 5 on both sides
So x= 136,000
There were 136,000 cattle between 700 and 799 pounds