A man attempts to pick up his suitcase of weight w_s by pulling straight up on the handle. (Part A figure) However, he is unable
to lift the suitcase from the floor. Which statement about the magnitude of the normal force n acting on the suitcase is true during the time that the man pulls upward on the suitcase?
A. The magnitude of the normal force is equal to the magnitude of the weight of the suitcase.
B. The magnitude of the normal force is equal to the magnitude of the weight of the suitcase minus the magnitude of the force of the pull.
C. The magnitude of the normal force is equal to the sum of the magnitude of the force of
the pull and the magnitude of the suitcase's weight.
D. The magnitude of the normal force is greater than the magnitude of the weight of the suitcase
A. The magnitude of the normal force is equal to the magnitude of the weight of the suitcase.
B. The magnitude of the normal force is equal to the magnitude of the weight of the suitcase minus the magnitude of the force of the pull.
C. The magnitude of the normal force is equal to the sum of the magnitude of the force of
the pull and the magnitude of the suitcase's weight.
D. The magnitude of the normal force is greater than the magnitude of the weight of the suitcase
1 answer:
Answer:
B. The magnitude of the normal force is equal to the magnitude of the weight of the suitcase minus the magnitude of the force of the pull.
Explanation:
As we know that man tried to pull the suitcase in upward direction
so here we can say that net upward force on the suitcase applied by the man is not as sufficient that it will counter balance the weight of the suitcase
So here the net force on the suitcase will be zero and the force equation is given as
so we have
so correct answer will be
B. The magnitude of the normal force is equal to the magnitude of the weight of the suitcase minus the magnitude of the force of the pull.
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Answer:
Magnetic force, F = 0.24 N
Explanation:
It is given that,
Current flowing in the wire, I = 4 A
Length of the wire, L = 20 cm = 0.2 m
Magnetic field, B = 0.6 T
Angle between force and the magnetic field, θ = 30°. The magnetic force is given by :
F = 0.24 N
So, the force on the wire at an angle of 30° with respect to the field is 0.24 N. Hence, this is the required solution.
Answer:
The value of tension on the cable T = 1065.6 N
Explanation:
Mass = 888 kg
Initial velocity ( u )= 0.8
Final velocity ( V ) = 0
Distance traveled before come to rest = 0.2667 m
Now use third law of motion =
- 2 a s
Put all the values in above formula we get,
⇒ 0 = - 2 × a ×0.2667
⇒ a = 1.2
This is the deceleration of the box.
Tension in the cable is given by T = F = m × a
Put all the values in above formula we get,
T = 888 × 1.2
T = 1065.6 N
This is the value of tension on the cable.