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2 years ago

If the clothing maker bought 500 m2 of this fabric, how much money did he lose? Use 1tepiz=0.625dollar and 0.9144m=1yard.'

1 answer:

3 0

1 yard^2 = 0.8361m^2.?
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

So he spent (.625 x 400) = $250.00 per m^2. 
He paid out (500 x 250) = $125,000 on the deal. 
He received (500 / 0.8361) = 598.014592 yard^2 of fabric. 
That would have cost (598.014592 x 120) = $71,761.75 locally. 
He lost (125,000 - 71,761.75) = $53,238.25 on the deal. 

You can rework with the incorrect conversion factor.

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Answer:

The charge to mass ratio is $-1.76\times10^{11}$

Explanation:

$Mass\ of\ electron=m_e=9.11\times10^{-31} kg\\ Charge\ of\ the\ electron=q_e=-1.60\times10^{-19} C\\$

We need to find how much charge is contained in the electron per unit of mass, to do this we divide the charge in an electron and the mass of an electron:

$\frac{Charge\ of\ electron}{Mass\ of\ electron}=\frac{q_e}{m_e}\frac{C}{kg}=\frac{-1.60\times10^{-19} C}{9.11\times10^{-31} kg}=-1.76\times10^{11} \frac{C}{kg}$

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2 years ago

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Answer:

(a): The frequency of the waves is f= 0.16 Hz

Explanation:

T/4= 1.5 s

T= 6 sec

f= 1/T

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2 years ago

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⦁ A speed skater increases her speed form 10 m/s to 12.5 m/s over a period of 3 seconds while coming out of a curve of 20 m radi

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7.85 m/s^2

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⇒ $a_r =\frac{12.5^2}{20}$

= 7.81 m/s^2

total acceleration

$a_T= \sqrt{a_t^2+a_r^2}$

putting values we get

$a_T= \sqrt{0.83^2+7.81^2}$

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Consider a 5kg rock and a 4.5g piece of paper held at the same height above the ground. What is true about the gravitational fie

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Answer:

The gravitational field at any point is independent of the objects placed at that point such as a stone or paper.

And, also the gravitational force acting on a body is determined by the intensity of the field at that point.

Explanation:

Given,

The gravitational force between two bodies separated by a distance r is given by the relation,

F = GMm / r²

Where,

M - the mass of the Earth

m - the mass of the object

r - the distance between the center of masses

Let m₁ be the mass of rock. Then force acting on the rock is given by

F = m₁a

The gravitational force between the stone and Earth is given by

F = GMm₁ / r²

Equating these two forces

m₁a = GMm₁ / r²

Canceling out the mass of the stone.

This shows that the force component acceleration is independent of the mass of the stone.

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And, also the gravitational force acting on a body is determined by the intensity of the field at that point.

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