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guapka [62]
2 years ago
8

The image on the left shows the charges on a balloon after it’s been rubbed with a wool cloth. The image on the right is a piece

of tissue paper. What will happen to the tissue paper as it approaches the balloon and why?
Physics
2 answers:
forsale [732]2 years ago
7 0

Answer: The tissue paper will stick to the balloon because it is positively charged.

Explanation:

When the balloon is rubbed with a wool cloth, then the balloon will have more negative charges than the positive charges.

There is no charge on the tissue paper. It is neutral. When it approaches to the balloon then the additional negative charge on the balloon will attract the positive charge in the tissue paper.

The tissue paper will stick to the balloon because it is positively charged.

taurus [48]2 years ago
3 0

When wool is rubbed with a balloon, the wool is left with a positive charge as electrons have travelled from the wool to the balloon which means the balloon now has a negative charge.

Now that the balloon has a negative charge, you need to know:
The tissue paper originally contains electrons and protons
The fact that the balloon has a negative charge, it will ATTRACT protons because protons are POSITIVE and electrons are NEGATIVE.
So once they are attracted, they will move closer to one another.
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Charge q1 is distance r from a positive point charge Q. Charge q2=q1/3 is distance 2r from Q. What is the ratio U1/U2 of their p
worty [1.4K]

We have that The ratio U1/U2 of their potential energies due to their interactions with Q is

  • U1/U2=6
  • U1/U2=6

From the question we are told that

Question 1

Charge q1 is distance r from a positive point charge Q.

Question 2

Charge q2=q1/3 is distance 2r from Q.

Charge q1 is distance s from the negative plate of a parallel-plate capacitor.

Charge q2=q1/3 is distance 2s from the negative plate.

Generally the equation for the potential energy  is mathematically given as

U=\frac{-k*qQ}{r}

Therefore

The Equations of U1 and U2 is

For U1

U1=\frac{-k*q_1Q}{r}

For U2

U2=\frac{-k*q_1Q}{3*2r}

Since

U is a function of q and  q2=q1/3

Therefore

U1/U2=6

For Question 2

For U1

U1=\frac{-k*q_1Q}{s}\\\\For U2\\\\U2=\frac{-k*q_1Q}{3*2r}

Therefore

U1/U2=6

For more information on this visit

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7 0
2 years ago
Based on the article “Will the real atomic model please stand up?,” why did J.J. Thomson experiment with cathode ray tubes? to s
PIT_PIT [208]

Answer:

B.) to determine that electric beams in cathode ray tubes were actually made of particles

Explanation:

This is the right answer i just took the quiz on edge.

3 0
2 years ago
A single-threaded power screw is 25 mm in diameter with a pitch of 5 mm. A vertical load on the screw reaches a maximum of 5 kN.
ioda

Answer:

0.243

Explanation:

<u>Step 1: </u> Identify the given parameters

Force (f) = 5kN, length of pitch (L) = 5mm, diameter (d) = 25mm,

collar coefficient of friction = 0.06 and thread coefficient of friction = 0.09

Frictional diameter =45mm

<u>Step 2:</u> calculate the torque required to raise the load

T_{R} = \frac{5(25)}{2} [\frac{5+\pi(0.09)(25)}{\pi(25)-0.09(5)}]+\frac{5(0.06)(45)}{2}

T_{R} = (9.66 + 6.75)N.m

T_{R} = 16.41 N.m

<u>Step 3:</u> calculate the torque required to lower the load

T_{L} = \frac{5(25)}{2} [\frac{\pi(0.09)(25) -5}{\pi(25)+0.09(5)}]+\frac{5(0.06)(45)}{2}

T_{L} = (1.64 + 6.75)N.m

T_{L} = 8.39 N.m

Since the torque required to lower the thread is positive, the thread is self-locking.

The overall efficiency = \frac{F(L)}{2\pi(T_{R})}

                        = \frac{5(5)}{2\pi(16.41})}

                        = 0.243

                 

8 0
2 years ago
What do we mean when we say that two light rays striking a screen are in phase with each other? What do we mean when we say that
galina1969 [7]

Answer: When the electric field due to one is a maximum, the electric field due to the other is also a maximum, and this relation is maintained as time passes. They alternatively reinforce and cancel each other.

Explanation:

In a wave, the phase, is an arbitrary time reference, used to locate a given point of the wave in time, within a cycle.

Two waves can travel at the same speed, or even have the same wavelength, but this is not enough to be sure that at a given point in time, both waves will be in their maximum, as it only can be determined from the phase of the waves.

So, only when the waves reach at the same point in time at the same amplitude, we can say that they arrive in phase, in a constructive interference.

8 0
2 years ago
A city uses a water tower to store water for times of high demand. When demand is light, water is pumped into the tower. When de
love history [14]

Answer:

The height of the tower will be 35.714 m

Explanation:

We have given gauge pressure P=350kPa=350\times 10^3Pa

Density of water \rho =1000kg/m^3

We have to find the height of the tower h

We know that gauge pressure is given by P=\rho gh

350\times 10^3=100 0\times 9.8\times h

h=35.714m

So the height of the tower will be 35.714 m

6 0
2 years ago
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