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The solar panels used by Mark function because of the photoelectric effect. Light shines on the cells causing electrons to be ej
2 answers:
Answer:
A) Ultraviolet
Explanation:
As per Einstein equation of photoelectric effect we know that
here we know that
= frequency of incident photons
= work function of metal
= kinetic energy of electrons
now we know that when light of sufficient energy falls on the solar plates then electrons will come out and current flow in the solar panel
So here out of all three option maximum energy is for ultraviolet so we need ultraviolet light for the phenomenon of photoelectric effect.
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Answer
given,
Mass of Kara's car = 1300 Kg
moving with speed = 11 m/s
time taken to stop = 0.14 s
final velocity = 0 m/s
distance between Lisa ford and Kara's car = 30 m
a) change in momentum of Kara's car
Δ P = m Δ v
Δ P = - 1.43 x 10⁴ kg.m/s
b) impulse is equal to change in momentum of the car
I = - 1.43 x 10⁴ kg.m/s
c) magnitude of force experienced by Kara
I = F x t
I is impulse acting on the car
t is time
- 1.43 x 10⁴= F x 0.14
F = -1.021 x 10⁵ N
negative sign represents the direction of force
I assume the x-y axis are tilted such that the x-axis is parallel to the surface of the hill while the y-axis is perpendicular to it.
In this case, the x-component of the weight is given by:
where
m is the mass of the car
g is the acceleration of gravity
is the angle of the hill
Substituting numbers into the formula, we find
In this case, the x-component of the weight is given by:
where
m is the mass of the car
g is the acceleration of gravity
Substituting numbers into the formula, we find
Answer:
Explanation:
Newton's law of universal gravitation states that the force experimented by a satellite of mass m orbiting Mars, which has mass at a distance r will be:
where is the gravitational constant.
This force is the centripetal force the satellite experiments, so we can write:
Putting all together:
which means:
Which for our values is:
Since this distance is measured from the center of Mars, to have the height above the Martian surface we need to substract the radius of Mars R=3389.5 km , which leaves us with: