A water park is designing a new water slide that finishes with the rider flying horizontally off the bottom of the slide. The sl
1 answer:
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Answer:
Explanation:
Let m is the mass of both cars. The first car is moving with speed v and the other car is moving with speed 2v. The only force acting on both cars is the centripetal force.
For faster car on the road,
v = 2v
..........(1)
For the slower car on the road,
............(2)
Equation (1) becomes,
So, the frictional force required to keep the slower car on the road without skidding is one fourth of the faster car.
The temperature of the gas is about 600 K
The Ideal Gas Law that needs to be recalled is:
<em>P = Pressure (Pa)</em>
<em>V = Volume (m³)</em>
<em>n = number of moles (moles)</em>
<em>R = Gas Constant (8.314 J/mol K)</em>
<em>T = Absolute Temperature (K)</em>
Let us now tackle the problem !
<u><em>Question (Translation):</em></u>
<em>A total of 0.2 moles of ideal gas are in containers with volume of 10 liters and a pressure of 1 atm. What is the temperature of the gas?</em>
<u>Given:</u>
number of moles = n = 0.2 moles
volume of gas = V = 10 liters
pressure of gas = P = 1 atm
gas contant = R = 0.0821 L.atm/mol.K
<u>Unknown:</u>
temperature of gas = T = ?
<u>Solution:</u>
- Minimum Coefficient of Static Friction : brainly.com/question/5884009
- The Pressure In A Sealed Plastic Container : brainly.com/question/10209135
- Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
Grade: High School
Subject: Physics
Chapter: Pressure
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant , Liquid , Pressure
Since you solved a and b I will start with part c.
Part C
To answer this question we need to find zeros of a velocity function:
We can factor this polynomial:
Now it's pretty easy to find zeros. This function will be equal to zero when any of the factors are equal zero.
We solve these two equations and we get our zeros:
The particle is at rest at t=0 and t=3/2.
Part D
To solve this we need to determine when our velocity function is greater than zero. We will use factored form.
We determine when each factor is greater than zero and with that information, we build the following table:
We can see, from the table, that our function is positive when
and t>3/2.
That is the range in which particle is moving in positive direction.
Part E
We know that distance traveled is given with:
We simply plug in t=12 to find total distance traveled:
Part F
We know that acceleration is defined as a rate of change of velocity.
We find acceleration by taking the first derivative of velocity with respect to time.
To find acceleration after 1 second we simply plug in t=1s in above equation:
Part C
To answer this question we need to find zeros of a velocity function:
We can factor this polynomial:
Now it's pretty easy to find zeros. This function will be equal to zero when any of the factors are equal zero.
We solve these two equations and we get our zeros:
The particle is at rest at t=0 and t=3/2.
Part D
To solve this we need to determine when our velocity function is greater than zero. We will use factored form.
We determine when each factor is greater than zero and with that information, we build the following table:
We can see, from the table, that our function is positive when
That is the range in which particle is moving in positive direction.
Part E
We know that distance traveled is given with:
We simply plug in t=12 to find total distance traveled:
Part F
We know that acceleration is defined as a rate of change of velocity.
We find acceleration by taking the first derivative of velocity with respect to time.
To find acceleration after 1 second we simply plug in t=1s in above equation: