<u>Events</u> A and B are called <u>independent</u>, when

otherwise events A and B are <u>dependent</u>.
The events A, B and A∩B are:
- A - Jane will go to a ballgame on Monday;
- B - Kate will go to a ballgame on Monday;
- A∩B - Kate and Jane both go to the ballgame on Monday.

Answer: events A and B are dependent
Answer:
see explaination
Step-by-step explanation:
Here the null hypothesis is that the PCB survives against the alternate that the PCB 'does not survive'. The test says that the PCB will survice if it is classified as 'good'; or, it will not survive if it is classifies as 'bad'.
a. The Type II error is the error committed when a PCB which cannot actually survive is classified as 'good'.
b. Therefore P(Type II error) = P(The PCB is classified as 'good' | PCB does not survives) = 0.03.
Question:
Read the excerpt from Julius Caesar, act 1, scene 2.
CASSIUS: ‘Tis just; And it is very much lamented, Brutus, That you have no such mirrors as will turn Your hidden worthiness into your eye, That you might see your shadow. I have heard 5 Where many of the best respect in Rome– Except immortal Caesar‐speaking of Brutus, And groaning underneath this age’s yoke, Have wished that noble Brutus had his eyes.
BRUTUS: Into what dangers would you lead me, Cassius, 10 That you would have me seek into myself For that which is not in me?
CASSIUS: Therefore, good Brutus, be prepared to hear. And since you know you cannot see yourself So well as by reflection, I, your glass, 15 Will modestly discover to yourself That of yourself which you yet know not of.
Answer:
The correct choice is D)
Explanation:
Cassius speaks of Brutus as one who is unable to see or know his own value and presumes to help him therewith. He does this by pointing out that many of the well respected people in Rome wish that he were in Caesars shoes as King.
Cheers!
Step-by-step explanation:
0.6/100= 0.006 should be multiplied to decrease by 0.6%
We are asked to solve for:
P (sand | positive)
So, we solve this by:
P (sand | positive) = P (sand) x P (positive for sand)
P (sand | positive) = 0.26 (0.75)
P (sand | positive) = 0.195
The probability is 0.195 or 19.5%.