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solniwko [45]
2 years ago
8

When Katie was visiting her grandpas farm she saw the farm only raised hands and pigs. Katie counted 32 heads and 100 feet in th

e backyard. How many hands and pigs were there in the backyard
Mathematics
1 answer:
QveST [7]2 years ago
8 0

There were 14 hens and 18 pigs in the backyard

Step-by-step explanation:

Katie was visiting her grandpas farm

  • She saw only hens and pigs
  • Katie counted 32 heads and 100 feet in the backyard

We need to find how many hens and pigs in the backyard

Assume that there are x hens and y pigs in the backyard

∵ There are x hens and y pigs in the backyard

∵ There are 32 heads

∴ x + y = 32 ⇒ (1)

∵ Each hen has 2 feet

∵ Each pig has 4 feet

∵ There are 100 feet

∴ 2x + 4y = 100 ⇒ (2)

Let us solve the system of equations to find how many hens and pigs

Multiply equation (1) by -2 to eliminate x

∴ -2x - 2y = -64 ⇒ (3)

- Add equations (2) and (3)

∴ 2y = 36

- Divide both side by 2

∴ y = 18

Substitute the value of y in equation (1) to find the value of x

∵ x + 18 = 32

- Subtract 18 from both sides

∴ x = 14

There were 14 hens and 18 pigs in the backyard

Learn more:

You can learn more about the system of equations in brainly.com/question/2115716

#learnwithBrainly

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A shoe manufacturer compared material A and material B for the soles of shoes. Twelve volunteers each got two shoes. The left wa
sveta [45]

Answer:

a) Are dependent since we are mesuring at the same individuals but on different times and with a different method

b) If we see the qq plot we don't have any significant deviation for the values and we don't have any heavy tail so we can conclude that we can approximate the differences with the normal distribution.

c) p_v =P(t_{(12)}>0.969) =0.353

So the p value is higher than the significance level given, so then we can conclude that we FAIL to reject the null hypothesis. So we can conclude that the mean differences is NOT significantly different from 0 .

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations (This problem) we can use it.  

The Q-Q plot, or quantile-quantile plot, "is a graphical tool to help us assess if a set of data plausibly came from some theoretical distribution such as a Normal or exponential".

Let put some notation  

x=value for A , y = value for B

A: 379, 378, 328, 372, 325, 304, 356, 309, 354, 318, 355, 392

B: 372, 376, 328, 368, 283, 252, 369, 321, 379, 303, 328, 411

(a) Are the two samples paired or independent? Explain your answer.

Are dependent since we are mesuring at the same individuals but on different times and with a different method

(b) Make a normal QQ plot of the differences within each pair. Is it reasonable to assume a normal population of differences?

The first step is calculate the difference d_i=A_i-B_i and we obtain this:

d: 7,2,0,4,42,52,-13,-12,-25,15,27,-19

In order to do the qqplot we can use the following R code:

d<-c(7,2,0,4,42,52,-13,-12,-25,15,27,-19)

qqnorm(d)

And the graph obtained is attached.

If we see the qq plot we don't have any significant deviation for the values and we don't have any heavy tail so we can conclude that we can approximate the differences with the normal distribution.

(c) Choose a test appropriate for the hypotheses above and justify your choice based on your answers to parts (a) and (b). Perform the test by computing a p-value, make a test decision, and state your conclusion in the context of the problem

The system of hypothesis for this case are:

Null hypothesis: \mu_A- \mu_B = 0

Alternative hypothesis: \mu_A -\mu_B \neq 0

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{80}{12}=6.67

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =23.849

The 4 step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{6.67 -0}{\frac{23.849}{\sqrt{12}}}=0.969

The next step is calculate the degrees of freedom given by:

df=n-1=12-1=11

Now we can calculate the p value, since we have a two tailed test the p value is given by:

p_v =P(t_{(12)}>0.969) =0.353

So the p value is higher than the significance level given, so then we can conclude that we FAIL to reject the null hypothesis. So we can conclude that the mean differences is NOT significantly different from 0 .

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2x3=6x3=18 u always do PEMDAS,
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<span>83.03 acres. To solve this, first calculate how many square feet that central park covers. Just multiply its length and width. So 1.37x10^4 * 2.64x10^2 = 3.6168x10^6 Now divide its area in square feet by the number of square feet in an acre. 3.6168x10^6 / 4.356x10^4 = 8.303x10^1 = 83.03</span>
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Grandpa ernie is shrinking! Over the past 4 years, his hight decressed by a total of 2.4cm. It decresed by the same amount each
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Answer: 0.6 cm

Step-by-step explanation:

Given : Over the past 4 years, Grandpa Ernie's height decreased by a total of 2.4 cm.

If  the height is decreased by the same amount each year.

Then, the change in Grandpa Ernie's height each year will be =

Total decrease in height ÷ 4

= 2.4 cm  ÷  4  = 0.6 cm

Hence, the  change in Grandpa Ernie's height each year = 0.6 cm

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Shelter A has a capacity of 300 beds and is 80% occupied. Shelter B is 45% occupied. The ratio of the occupancy of shelter A to
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Answer:there are 900 beds in shelter B

Step-by-step explanation:

Shelter A has a capacity of 300 beds and is 80% occupied. This means that the number of beds in Shelter A that would be

80/100 × 300 = 0.8 × 300 = 240 beds.

Let x represent the capacity of Shelter B. Shelter B is 45% occupied. It means that number of beds in Shelter B that would be occupied is

45/100 × x = 0.45 × x = 0.45x beds.

Total occupancy of shelter A and shelter B would be

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The ratio of the occupancy of shelter A to shelter B is 16:27

Total ratio of occupancy = 16 + 27 = 43

Therefore

27/43 × (240 + 0.45x) = 0.45x

27(240 + 0.45x) = 0.45x × 43 = 19.35x

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6480 = 19.35x - 12.15x = 7.2x

x = 6480/7.2 = 900

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