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serg [7]
1 year ago
5

A football player kicks a 0.41-kg football initially at rest; and the ball flies through the air. If the kicker's foot was in co

ntact with the ball for 0.051 s and the ball's initial speed after the collision is 21 m/s, what was the magnitude of the average force on the football?
Physics
1 answer:
LUCKY_DIMON [66]1 year ago
4 0

Answer:

Average force on the football = 168.82 N

Explanation:

Force = Mass x Acceleration

F = ma

Mass, m = 0.41 kg

We have equation of motion, v = u + at

Initial velocity, u = 0 m/s

Final velocity, v = 21 m/s

Time, t = 0.051 s

Substituting

                  21 = 0 + a x 0.051

                     a = 411.76 m/s²

Substituting in force equation,

                   F = ma = 0.41 x 411.76 = 168.82 N

Average force on the football = 168.82 N

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A bucket of water experiencing a gravitational force of 525 N is pulled from a water well. Net force in the Y direction is 45 N
vivado [14]

Answer:

T = 570 N

Explanation:

Given that,

The gravitational force acting on a bucket of water = 525 N

Net force in the Y direction is 45 N

We need to find the magnitude of the force of tension. It can be calculated as :

45 = T - 525

T = 525 + 45

T = 570 N

Hence, the force of tension is 570 N.

7 0
1 year ago
A computer that is 87% efficient consumes 375 kWh of energy. How much useful energy does it provide?
tekilochka [14]

Answer:

326.25 kWh

Explanation:

Efficiency of a machine is defined as the ratio of useful energy to that of the energy consumed by the machine.

Here, efficiency is given as 87% and the energy consumed by the computer is 375 kWh.

Efficiency, \eta=\frac{\textrm{Useful energy}}{\textrm{Energy consumed}}

Plug in the values of \eta=0.87 and 375 kWh for energy consumed. Solve for useful energy. This gives,

Efficiency, \eta=\frac{\textrm{Useful energy}}{\textrm{Energy consumed}}\\ 0.87=\frac{\textrm{Useful energy}}{375}\\ \textrm{Useful energy}=0.87\times 375=326.25 \textrm{ kWh}

Therefore, the useful energy provided by the computer is 326.25 kWh.

3 0
1 year ago
Why wheat flour is usually passed near a magnet before being packed?
densk [106]
Becasue steel particles may contaminate the flour.
8 0
2 years ago
Calculate the density of mercury if 500 cm3
notka56 [123]

Answer:

The density of the mercury is 13.2 g/cm³

Explanation:

Density is a measurement that compares the amount of matter an object

has to its volume

Density is equal to mass divided by volume

We need to find the density of mercury if 500 cm³ has a mass of

6.60 kg in g/cm

We must to change The kilogram to grams

The mass of mercury is 6.60 kilograms

1 kilogram = 1000 grams

6.60 kilograms = 6.60 × 1000 = 6600 grams

Density = mass ÷ volume

The volume of the mercury is 500 cm³

The density = 6600 ÷ 500

The density = 13.2 g/cm³

<em>The density of the mercury is 13.2 g/cm³ </em>

5 0
2 years ago
One of the largest barometers ever built was an oil-filled barometer constructed in Leicester, England in 1991. The oil had a he
ZanzabumX [31]

Answer:

ρ = 830.32 kg/m³

Explanation:

Given that

Oil head = 12.2 m

h= 12.2 m

Pressure P = 1.013 x 10⁵ Pa

Lets take density of the liquid =ρ

The pressure due to liquid P given as

P = ρ g h

Now by putting the all values in the above equation

1.013 x 10⁵ Pa = ρ x 10 x 12.2                 ( take g =10 m/s²)

ρ = 830.32 kg/m³

Therefore the density of oil is 830.32  kg/m³

5 0
2 years ago
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