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Dmitriy789 [7]
2 years ago
9

To a cyclist riding due west with a speed of 4 m/s a wind appears to

Physics
1 answer:
rusak2 [61]2 years ago
7 0

Answer:

The actual velocity of the wind blowing from south to west is, V = 3.08 m/s

Explanation:

Given data,

The velocity of the cyclist towards west, v = 4 m/s

The wind appears to blow from the south, U = 2 m/s

Let Ф be the angle formed by the direction of the wind with the west axis,

Therefore, the actual velocity of the wind is,

                                 V = (v - U) secФ

                                     = 2 sec Ф

Le the value of Ф = 30°, (The student may add the necessary value of Ф)

                                  V =  2(1.54)

                                   V = 3.08 m/s

Hence, the actual velocity of the wind blowing from south to west is, V = 3.08 m/s

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A champion athlete can produce one horsepower (746 W) for a short period of time. The number of 16-cm-high steps a 70-kg athlete
erastovalidia [21]

Answer:

407 steps

Explanation:

From the question,

P = mgh/t........... Equation 1

Where P = power, m = mass, g = acceleration due to gravity, h = height, t = time.

Make h the subject of the equation

h = Pt/mg............. Equation 2

Given: P = 746 W, t = 1 minute = 60 seconds, m = 70 kg.

Constant: g = 9.8 m/s²

Substitute into equation 2

h = 746(60)/(70×9.8)

h = 44760/686

h = 65.25 m

h = 6525 cm

number of steps = 6525/16

number of steps = 407 steps

6 0
2 years ago
A cylindrical bar of steel 10.1 mm (0.3976 in.) in diameter is to be deformed elastically by application of a force along the ba
amm1812

Answer:

14778.29 N

Explanation:

Diameter, d=10.1mm= 10.1*10^{-3}m

Since stress, \sigma= \frac {F}{A} where F is force, A is area and since specimen is cylindrical,  

A= \pi *(d/2)^{2}  Therefore, \sigma= \frac {F}{\pi*(0.5d)^{2}}

Also strain \epsilon= \frac { \triangle L}{L} where L is length

Poison’s ratio,v is the ratio of lateral strain to longitudinal strain hence

V= -\frac {\epsilon_{x}}{\epsilon_{z}}= \frac {\triangle dl_{o}}{d \triangle l}

From Hooke’s law, \sigma=E \epsilon_{z}

Conclusively, E* \epsilon_{z}=E* \frac {- \epsilon_{x}}{v}=\frac {F}{\pi*(0.5d)^{2}}

\frac {4F}{ \pi *d^{2}}=- \frac {E \triangle d}{vd}

F=- \frac {\pi *Ed \triangle d}{4v}

F= - \frac {\pi *207*10^{9} *10.1*10^{-3}* (-2.7*10^{-6})}{4*0.3}= 14778.29N

Therefore, required force F is 14778.29 N

3 0
2 years ago
There is a 120 V circuit in a house that is a dedicated line for the dishwasher, meaning the dishwasher is the only resistor on
aliya0001 [1]

The info given in the question:

Voltage= 120V

Current=18A

Now we have to find the resistance. To find it use the following formula:

V=IR

Now making R to be the subject of the formula

R=V/I

R=120/18

The answer is 6.67 ohms

As dishwasher is the only resistor in the line the voltage drop is going to be 120V. The resistance values determines the hindrance that is present in the circuit that opposes the free flowing electrons  

7 0
2 years ago
Read 2 more answers
Two students are playing paddle ball with a 5 kg spongy ball. If the ball is thrown at the batter with a speed of 5 m/s and boun
fenix001 [56]

Answer:

75 kgm/s

Explanation:

Impulse: This can be defined as the product of mass and change in velocity. The S.I unit is kgm/s.

From the question,

I = m(v-u)................... Equation 1

Where I = impulse, m = mass, v = final velocity, u = initial velocity.

Let the direction of the initial velocity be the positive direction.

Given: m = 5 kg, v = -10 m/s (bounce off), u = 5 m/s.

Substitute into equation 1

I = 5(-10-5)

I = 5(-15)

I = -75 kgm/s.

The negative sign tells that the impulse act in the same direction as the final velocity of the ball

Hence,

I = 75 kgm/s

3 0
2 years ago
When working with a razor blade or exacto knife --
stich3 [128]

Answer:

last answer

Explanation:

gripping it with the blade facing downward is the most efficient and safe way to use an exacto knife

6 0
2 years ago
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