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NeX [460]
2 years ago
7

(a) Use the fundamental theorem of algebra to determine the number of roots for 2x^2 + 4x + 7

Mathematics
1 answer:
zysi [14]2 years ago
4 0

Answer:

Step-by-step explanation:

A 2nd order polynomial such as this one will have 2 roots; a 3rd order polynomial 3 roots, and so on.

The quadratic formula is one of the faster ways (in this situation, at least) in which to find the roots.  From 2x^2 + 4x + 7 we get a = 2, b = 4 and c = 7.

Then the discriminant is b^2 - 4ac, or, here, 4^2 - 4(2)(7), or -40.  Because the discriminant is negative, we know that the roots will be complex and unequal.

Using the quadratic formula:

       -4 ±√[-40]         -4 ± 2i√10

x  = ------------------ = ------------------

                4                       4

                                       -2 ± i√10

Thus, the roots are x = ------------------

                                               2

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2 years ago
Morgan, Dakota and Taylor showed their work solving the equation 7x + 5x +1= 73. Identify the student with the invalid first ste
Pavel [41]

Answer:

Morgan, Dakota and Taylor showed their work solving the equation 7x + 5x +1= 73. Identify the student with the invalid first step and justify your reasoning. Morgan 7x + 5x + 1 = 73 12x + 1 = 73 Dakota 7x + 5x + 1 = 73 7x + 6x = 73 Taylor 7x + 5x + 1 = 73 7x + 5x = 72​

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
If Karim has eight male cousins and twelve female cousins,what fraction of his cousins are female?
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A gardener wants to plant 122500 trees in his field in such a way that the number of trees in a row is equal to the number of ro
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Given that the gardener wants the number of trees in each raw to be equal to the number of rows, then let the number of in each row be x this means that the number of rows will be x.
Thus the total number of trees will be:
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hence:
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6 0
2 years ago
Find the solution set of the following equations: <br><br>2y=2x+7<br><br>X=y+2
kirill115 [55]

Answer:

The system of equations has no solution.

Step-by-step explanation:

Given the system of equations

2y = 2x+7

x = y+2

solving the system of equations

\begin{bmatrix}2y=2x+7\\ x=y+2\end{bmatrix}

Arrange equation variables for elimination

\begin{bmatrix}2y-2x=7\\ -y+x=2\end{bmatrix}

Multiply -y+x=2 by 2:  -2y+2x=4

\begin{bmatrix}2y-2x=7\\ -2y+2x=4\end{bmatrix}

so adding

-2y+2x=4

+

\underline{2y-2x=7}

0=11

so the system of equations becomes

\begin{bmatrix}2y-2x=7\\ 0=11\end{bmatrix}

0 = 11 is false, therefore the system of equations has no solution.

Thus,

No Solution!

3 0
2 years ago
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