A tire company measures the tread on newly-produced tires and finds that they are normally distributed with a mean depth of 0.98
1 answer:
Answer:
0.212 is the probability that a randomly selected tire will have a depth less than 0.70 mm.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 0.98 mm
Standard Deviation, σ = 0.35 mm
We are given that the distribution of tire tread is a bell shaped distribution that is a normal distribution.
Formula:
a) P(depth less than 0.70 mm)
P(x < 0.70)
Calculating from normal z table, we have:
Thus, this event is not unusual and will not warrant a refund.
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Answer:
The equation is found to be:
y(20) = 1241.34
Step-by-step explanation:
The given data is:
x: 3 7 11 14 17
y: 83 142 301 450 722
Now, we find sum summation values, relevant to the formula of exponential regression model, using calculator:
∑ ln y = 27.77305, ∑x ln y = 308.1494, ∑x = 52, ∑ x² = 664
and, n = no. of data points = 5
Now, we use formulae of exponential regression model to find out values of constant:
b = (n∑x lny - ∑x ∑ln y)/[n∑x² - (∑x)²]
b = [(5)(308.1494) - (52)(27.77305)]/[(5)(664) - (52)²]
b = 0.16
Now, for a;
a = (∑ln y - b∑x)/n
Therefore,
a = [(27.77305) - (0.16)(52)]/5
a = 3.9
For, α:
α = e^a = e^3.9
α = 50.6
So, the final equation of exponential regression model is given as:
Now, we find value of y for x = 20:
y(20) = (50.6) e^(0.16*20)
<u>y(20) = 1241.34</u>
Answer:
Step-by-step explanation:
Given that Darcie wants to donate minimum 3 blankets to donate to a homeless shelter. No of days left =60
No of days to complete one blanket = 1/(1/15) = 15 days
Hence in 60 days she has to complete ≥3 blankets
No of days she has to utilize for this will be ≥3(15)=45
No of days she can skip crocheting ≤15
Let x be the no of days crocheted and y no of days skipped
Then x+y≤60
See the graph attached as x axis for days crocheted and y for days skipped
No of blankets can be either 3 or 4.
