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Igoryamba
2 years ago
4

Omar has a gift card for $40.00 at a gift shop. Omar wants to buy a hat for himself for $13.50. For his friends, he would like t

o buy souvenir bracelets, which are $3.25 each. All prices include taxes.
Which inequality can be used to solve for how many bracelets Omar can buy?


A. 3.25x + 13.50 ≤ 40

B. 3.25x + 13.50 ≥ 40

C. 13.50x + 3.25 ≤ 40

D. 13.50x + 3.25 ≥ 40
Mathematics
1 answer:
pychu [463]2 years ago
4 0

Answer:

A

Step-by-step explanation:

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A store sells a 33-pound bag of oranges for \$ 3.60$3.60 and a 55-pound bag of oranges for \$ 5.25$5.25. What is the difference
katrin [286]

Answer:

0.01364

Step-by-step explanation:

It is given that,

A store sells a 33-pound bag of oranges for $3.60 and a 55-pound bag of oranges for $5.25.

Price per pound of 33 pound bag is 3.60/33 = 0.10909 price per pound

Price per pound of 55 pound bag of oranges is 5.25/55 = 0.09545 price per pound

Difference between price per pound for the 33-pound bag of oranges and the price per pound for the 55-pound bag of oranges is :

D = 0.10909 - 0.09545

D = 0.01364

Therefore, this is the required solution.

3 0
2 years ago
A sample of size 60 from one population of weights had a sample average of 10.4 lb. and a sample standard deviation of 2.7 lb. A
Olegator [25]

Answer:

z=  0.278

Step-by-step explanation:

Given data

n1= 60 ; n2 = 100

mean 1= x1`= 10.4;     mean 2= x2`= 9.7

standard deviation  1= s1= 2.7 pounds ;  standard deviation 2= s2 = 1.9 lb

We formulate our null and alternate hypothesis as

H0 = x`1- x`2 = 0 and H1 = x`1- x`2 ≠ 0 ( two sided)

We set level of significance α= 0.05

the test statistic to be used under H0 is

z = x1`- x2`/ √ s₁²/n₁ + s₂²/n₂

the critical region is z > ± 1.96

Computations

z= 10.4- 9.7/ √(2.7)²/60+( 1.9)²/ 100

z= 10.4- 9.7/ √ 7.29/60 + 3.61/100

z= 0.7/√ 0.1215+ 0.0361

z=0.7 /√0.1576

z= 0.7 (0.396988)

z= 0.2778= 0.278

Since the calculated value of z does not fall in the critical region so we accept the null hypothesis H0 = x`1- x`2 = 0  at 5 % significance level. In other words we conclude that the difference between mean scores is insignificant or merely due to chance.

3 0
2 years ago
Use operations of decimal, fraction, and percent numbers and your models from Part (b) to solve the following application proble
KIM [24]
2. $5.10 
4. 18%
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4 0
2 years ago
Ne Friday night, a group of friends bought 5 containers of popcorn and 4 granola bars at the movie theatre for $42.50. The next
Tomtit [17]

In this question , it is given that p represents cost of 1 container of popcorn . Therefore cost of 5 containers of popcorn = 5p and cost of 3 containers of popcorn = 3p .

And g represents cost of 1 container of granola bars. THerefore cost of 4 containers of granola bars = 4g and cost of 6 containers of granola bars = 6g .

According to the given question, the required linear equations are

5p+4g=42.50 , 3p+6g =34.50 .

And these are the the required system of linear equation .

4 0
2 years ago
A helicopter flies 8 km due north from A to B. It then flies 5 km from B to C and returns to A as shown in the figure. Angle ABC
In-s [12.5K]

Please consider the attached graph.

We have been given that a helicopter flies 8 km due north from A to B. It then flies 5 km from B to C and returns to A as shown in the figure. The measure of angle ABC is 150°. We are asked to find the area of triangle ABC.

We will use trigonometric area formula to solve our given problem.

A=\frac{1}{2}a\cdot c\cdot\text{sin}(b), where angle b is angle between sides a and c.

For our given triangle a=5,c=8 and measure of angle b is 150 degrees.

A=\frac{1}{2}(5)\cdot (8)\cdot\text{sin}(150^{\circ})

A=5\cdot 4\cdot(0.5)

A=10

Therefore, the area of the triangle ABC is 10 square kilo-meters and option 'c' is the correct choice.

6 0
2 years ago
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