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Firlakuza [10]
2 years ago
8

According to the reaction represented above, about how many grams of aluminum (atomic mass 27 g) are necessary to produce 0.50 m

ol of hydrogen gas at 25oC and 1.0 atm?
(A) 1.0 g
(B) 9.0 g
(C) 14 g
(D) 27 g
(E) 56 g
Chemistry
1 answer:
Dima020 [189]2 years ago
8 0

Answer:

9 grams are necessary to produce 0.50 mol of H₂

Explanation:

I guess, this can be a certain reaction to that:

6 HCl + 2Al → 2AlCl₃ + 3H₂

Let's think a rule of three:

If 3 moles of H₂ are produced by 2 moles of aluminum

0.5 moles of H₂ are produced by (0.5 . 2)/3 = 0.333 moles

Now that we have the moles, let's know the grams by this.

Molar mass . moles = grams

27 g/m .  0.3333 m = 9 g

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