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777dan777 [17]
2 years ago
7

Final Shot John Diggle needs to give up his trusted Glock for a more non-lethal weapon. Cisco Ramon builds him a stun gun that h

is claims matches the Glock shooting characteristics, including accuracy. Do these data representing "shot groups" give statistically significant evidence of a difference in accuracy between the two type?
Glock (cm): 9.3 16.7 7.1 14 5 6
Stun Gun (cm): 4.9 14.1 7 7.2 5.4 8.6

Write the Hypotheses:
H_0:_______________, the mean difference in ___________ between ____________ and ______________ is _______________
H_a:_______________, the mean difference in ___________ between ____________ and ______________ is _______________
Are the conditions for inference met? (draw a picture of the histograms)


Provide the calculations:
Sample mean diff:_________________________________
Standard err:_____________________________________
T-stat:__________________________________________
P-value:_________________________________________
Write your conclusion:
At the 5% level of significance, we ______________ that the mean difference in ___________ between ____________ and ______________ is _______________. We ________________________ the mean difference in ___________ between ____________ and ______________ is _______________. [P-value = ________ ]
Construct a 90% Confidence interval.

What does the interval mean in the context of the problem

We are 90% confident that the difference in mean _______________
For ________________________ is between ____________ and _______________ ___________________ than __________________.
Was Cisco correct, does John’s Stun Gun perform the same? Explain
Mathematics
1 answer:
lidiya [134]2 years ago
7 0
The h in p will start the p and the glock I believe
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Look at the figure. Which of the following segments is parallel to AB?
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I think it’s c and h
5 0
2 years ago
Round to the nearest ten thousand 905154
kolbaska11 [484]
You want to round 905,154 to the nearest ten-thousands place. The ten-thousands place in your number is shown by the bold underlined digit here:

9<em><u>0</u></em>5,154

    To round 905,154 to the nearest ten-thousands place...

    The digit in the ten-thousands place in your number is the 0. To begin the rounding, look at the digit one place to the right of the 0, or the 5, which is in the thousands place.

    Since the 5 is greater than or equal to 5, we'll round our number up by

        Adding 1 to the 0 in the ten-thousands place, making it a 1.

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The result is: 910,000.

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5 0
2 years ago
In a health club, research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard dev
Paha777 [63]

Answer:

0.3114

Option d is right

Step-by-step explanation:

Let X be the time spent on a treadmill in the health club

Given that  research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard deviation of 5.4 minutes

Also given that X is normal

the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill.

= P(30

round off to two decimals tog et

the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill is 0.31

Hence option d is right

3 0
2 years ago
Two independent simple random samples are taken to test the difference between the means of two populations whose variances are
My name is Ann [436]
I think it’s 72 degrees of freedom
3 0
2 years ago
The diameters of aluminum alloy rods produced on an extrusion machine are known to have a standard deviation of 0.0001 in. A ran
Ganezh [65]

Answer:

a) Hypothesis mean differs from 0.5025. Rejected

b) P-value = 0

c) 0.50456 < u < 0.50464

Step-by-step explanation:

Given:

- The standard deviation s.d = 0.0001 in

- The mean of the sample x = 0.5046 in

- Sample size n = 25

Find:

a) Test the hypothesis that mean rod. Assume two-sided alternative and significance level of 0.05.

b) Find the p-value for test in part

c) Construct a 95% two-sided confidence interval on the mean rod diameter.

Solution:

- The random variable X: the measurements for rod diameter follows a normal distribution:  

                                       X~ N( 0.5025 , 0.0001 )

- Testing H_o: u_o = 0.5025  , H_1 : u_o not equal 0.5025

- Compute the corresponding Z-score:

                             Z_o = (0.5046 - 0.5025) / 0.0001/sqrt(25)

                             Z_o = 105

- The Z score value with respect to significance level is:

                            Z_a/2 = Z_0.025 = 1.96

Hence, Z_o > Z_a/n

- The hypothesis H_o is rejected the mean differs from 0.5025.

- The corresponding P-Value is:

                            P-value = 2*(1 - sig(Z_o)) = 2*(1 - sig(105))

                           P-value = 2*(1-1) = 0

- The confidence interval is:

                 ( x - Z_a/2(s.d/sqrt(n)) < u <  ( x + Z_a/2(s.d/sqrt(n))

  ( 0.5046 - 1.96(0.0001/sqrt(25)) < u <  ( 0.5046 + 1.96(0.0001/sqrt(25))  

                              0.50456 < u < 0.50464

3 0
2 years ago
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