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gayaneshka [121]
2 years ago
7

Sandy went to the post office with $20. She mailed a package for $3.67. Write and solve an inequality to find the greatest amoun

t of $.37 stamps Sandy could have purchased?​
Mathematics
1 answer:
Eddi Din [679]2 years ago
4 0

Answer:

Step-by-step explanation:

Total money = $20

amount for mailing package = $ 3.67

Price for one stamp = $ 0.37

Let number of stamps be x,

Price for x stamps = $.037x

Price for x stamps + amount for package should not exceed $20

0.37x+3.67 ≤ 20

Solving for inequality,

x≤ 44.1

Since x should be whole number,

x ≤ 44

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Jeff brought a bottle of water for $2.He also brought some hot dogs for $3 each.Jeff did not spend more than $14 on the hot dog
Gala2k [10]
The answer would be D because 3h + 2 (water) has to be less than or equal to > 14
8 0
1 year ago
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Luke has 1/5 of a package of dried apricots. He divides the dried apricots equally into 4 small bags. Luke gives one of the bags
Ivahew [28]

Answer:

3/80

Step-by-step explanation:

If one fifth of apricots are split into 4 parts, each bag has 1/5 * 1/4 of the original apricots

1/5 * 1/4 = 1/20

Luke keeps 3/4 of those so that's

3/4 * 1/20 = 3/80

7 0
1 year ago
The U.S. Bureau of Labor Statistics reports that 11.3% of U.S. workers belong to unions (BLS website, January 2014). Suppose a s
andrezito [222]

Answer:

a) Null hypothesis:p \leq 0.113  

Alternative hypothesis:p > 0.113  

b) z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.13 -0.113}{\sqrt{\frac{0.113(1-0.113)}{400}}}=1.074  

The p value for this case would be given by:

p_v =P(z>1.074)=0.141  

c) For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%

Step-by-step explanation:

Information given

n=400 represent the random sample taken

X=52 represent the  workers belonged to unions

\hat p=\frac{52}{400}=0.13 estimated proportion of workers belonged to unions

p_o=0.113 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v represent the p value

Part a

We want to test if the true proportion of interest is higher than 0.113 so then the system of hypothesis are.:  

Null hypothesis:p \leq 0.113  

Alternative hypothesis:p > 0.113  

Part b

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.13 -0.113}{\sqrt{\frac{0.113(1-0.113)}{400}}}=1.074  

The p value for this case would be given by:

p_v =P(z>1.074)=0.141  

Part c

For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%

8 0
2 years ago
A high school coach needs to buy new athletic shorts for the 15 members of the basketball team. The coach must spend less than $
AfilCa [17]
If the budget is $200 and he have 15 members then we have divide the two. 200 / 15 = $13.33 per shorts. 15x =< $200. x represents 13.33. So the solution represents the coach may spend up to $13.33 per pair of shorts. If it was even 1 cent more than $13.33 than he wouldn't have enough.So he can spend up to $13.33 or less per pair of shorts.
5 0
2 years ago
Read 2 more answers
A 12-centimeter rod is held between a flashlight and a wall as shown. Find the length of the shadow on
choli [55]

Answer:

48 cm

Step-by-step explanation:

Given:

Distance of rod from the wall = 45 cm

Distance of rod from the light = 15 cm

Length of rod = 12 cm

We can see that <DAM and <BAF are equal

Also, <DMA and <BFM are equal because they are corresponding angles

To find the length of the shadow, let's take the equation

\frac{DM}{BF} = \frac{AM}{A.F}

Where.:

DM = ½ of length of the rod = ½*12 = 6

A.F = 15 + 45 = 60 cm

AM = 15 cm

Therefore,

\frac{DM}{BF} = \frac{AM}{A.F}

= \frac{6}{BF} = \frac{15}{60}

Cross multiplying, we have:

15 * B.F = 60 * 6

15 * B.F = 360

BF = \frac{360}{15}

BF = 24 cm

The shadow on the wall =

2 * BF

= 2 * 24

= 48 cm

The shadow on the wall is 48 cm

7 0
1 year ago
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