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frosja888 [35]
2 years ago
15

A chemical engineer calculated that 15.0 mol H2 was needed to react with excess N2 to prepare 10.0 mol NH3. But the actual yield

is 60.0%. Write a balanced chemical equation for the reaction. Is the amount of H2 needed to make 10.0 mol NH3 greater than, equal to, or less than 15 mol? How many moles of H2 are needed?
Chemistry
1 answer:
rjkz [21]2 years ago
8 0

Answer:

The actual number of moles is 9 moles.

It is less than 15

Number of moles needed is 9 moles

Explanation:

15H2 + 10N2 ——-> 10NH3

Now from the question, we can see that the percentage yield is 60%

The percentage yield can be calculated as actual moles of H2/Theoretical moles of H2 * 100%

From the equation, we can see that the theoretical number of moles of hydrogen is 15.

Now to get the actual : 60 = x/15 * 100

x = 9

The actual number of moles is 9 moles.

It is less than 15

Number of moles needed is 9 moles

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The volume of hcl gas required to react with excess ca to produce 11.4 l of hydrogen gas at 1.62 atm and 62.0 °c is ________ l.
seropon [69]

Answer:

22.8 L  

Step-by-step explanation:

We can use <em>Gay-Lussac's Law of Combining Volumes</em> to solve this problem:

Gases <em>at the same temperature and pressure</em> react in simple whole-number ratios.

1. Write the chemical equation.

Ratio:                 2 L                             1 L

          Ca(s) + 2HCl(g) ⟶ CaCl₂(s) + H₂(g)

V/L:                                                     11.4

2. Calculate the volume of HCl.

According to the law, 2 L of HCl form 1 L of H₂.

Then, the conversion factor is (2 L HCl/1 L H₂).

Volume of HCl = 11.4 L H₂ × (2 L HCl/1 L H₂)

                         = 22.8 L HCl

3 0
2 years ago
Identify the sets of quantum numbers that describe all the electrons in the ground state of a neutral beryllium atom, be. each s
Mkey [24]
<span>A beryllium atom has 4 electrons. 1, 0, 0, +1/2 1, 0, 0, -1/2 2, 0, 0, +1/2 2, 0, 0, -1/2</span>
8 0
2 years ago
A block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat. From this data, calc
GrogVix [38]

<u>Answer:</u>

Specific heat of a substance is the value that describe how the added heat energy of substance has the impact on its temperature.

Unit is <em>(\frac {J}{Kg.K})</em>

<em>C = Q/m. ∆T</em>

<em>C – Specific heat (\frac {J}{Kg.K})</em>

<em>Q- heat energy (J)</em>

<em>M – Mass (Kg)</em>

<em>∆T- change in temperature (K) </em>

<u>Explanation:</u>

<em>Given data:</em>

<em>M= 140 g = 0.14 Kg</em>

<em>Q – 1080 Joules.</em>

<em>∆T – 98.4 – 62.2 = 36.2</em>

Substituting  the given data in Equation

<em>Specific heat of Aluminium  = \frac {1080}{(0.14 \times 36.2)} = 213.10 (\frac {J}{Kg.K})</em>

3 0
2 years ago
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A common way of initiating certain chemical reactions with light involves the generation of free halogen atoms in solution. if δ
STatiana [176]

Answer: The longest wavelength of light that will produce free chlorine atoms in solution is 493 nm.

Explanation:

Cl_2\overset{h\nu}\rightarrow Cl^-,Delta H_{rxn}=242.8kJ/mol

Energy required to produce free chlorine atoms from one mole of chlorine gas :

= 242.8kJ = 242.8\times 1000=242800 Joules (1kJ=1000J)

1 mole = 6.022\times 10^{23} molecules

For 6.022\times 10^{23} molecules = 242,800 Joules

For one molecule of chlorine gas =  \frac{242800 Joules/mol}{6.022\times 10^{23} mol^{-1}}=40,318.83\times 10^{-23}Joules

According to photoelectric equation:

E=h\nu=\frac{hc}{\Lambda }

E = Energy of the photon of light used to produce free chlorine atoms

\nu= frequency of the light used to produce free chlorine atoms

h = Planck's constant =6.626\times 10^{-34}J.s, c = speed of light=3\times 10^8 m/s

\lambda = wavelength of the light used to produce free chlorine atoms

40,318.83\times 10^{-23}J=\frac{hc}{\Lambda }=\frac{6.626\times 10^{-34} J.s\times 3\times 10^8 m/s}{\lambda }

\lambda=0.0004930203\times 10^{-3} m=493.0203\times 10^{-9} m=493 nm

The longest wavelength of light that will produce free chlorine atoms in solution is 493 nm.

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2 years ago
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Anarel [89]
The rms speed of a gas can be calculated using the following rule:
Vrms = sqrt ( 3RT / M) where:
R is the gas constant = 8.314
T is the temperature = 29 + 273 = 302 degrees kelvin
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Substitute in the equation to get Vrms as follows:
Vrms = sqrt [(3*8.314*302) / (0.032)] = 485.05 meters/sec
7 0
2 years ago
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