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SIZIF [17.4K]
2 years ago
5

Two containers hold the same radioactive isotope. Container A contains 1000 atoms, and container B contains 500 atoms. Which of

the following statements about containers A and B is true? Two containers hold the same radioactive isotope. Container A contains 1000 atoms, and container B contains 500 atoms. Which of the following statements about containers A and B is true? The rate of decay of atoms (half-life) in container A is greater (or longer) than the rate of decay of atoms (half-life) in container B. The rate of decay of atoms (half-life) in container B is greater (or longer) than the rate of decay of atoms (half-life) in container A. The rate of decay of atoms (half-life) in container B is the same as the rate of decay of atoms (half-life) in container A.
Chemistry
2 answers:
Angelina_Jolie [31]2 years ago
6 0

Answer:

b

Explanation:

Sloan [31]2 years ago
3 0

Answer:

B

Explanation:

This is due to the differences in the concentrations of the radioactive isotopes in the two containers of the same volume. In container A, with a higher density of atoms, there is a higher chance of a neutron released in the decay of one atom, hitting another atom and splitting it. This is in comparison to container B that has fewer atoms that are widely dispersed due to the lower density. Atoms in cointainer A will therefore decay faster (shorter half-life) than atoms in container B.

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How many moles of KCl will be<br> produced from 15.0 g of KClO3?
slega [8]

Answer:

0.12 mol KCl

Explanation:

2 KClO3 (s)   2 KCl (s) + 3 O2 (g)

15 g                x mol

x g KCl = 15 g KClO3 x[ (1 mol KClO3)/ (122.5 g KClO3) ] x [(2 mol KCl)/ (2 mol KClO3)]

x g KCl = 0.12 mol KCl

7 0
2 years ago
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What element is used in bright flashing advertising signs
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The element used in advertising signs is neon.
4 0
2 years ago
The dipole moment (μ) of HBr (a polar covalent molecule) is 0.838D (debye), and its percent ionic character is 12.4 % . Estimate
myrzilka [38]

<span>When two electrical charges, of opposite sign and equal magnitude, are separated by a distance, a dipole is established. The size of a dipole is measured by its dipole moment (</span>μμ). Dipole moment is measured in Debye units, which is equal to the distance between the charges multiplied by the charge (1 Debye equals 3.34×10−30Cm3.34×10−30Cm). The dipole moment of a molecule can be calculated by Equation 1.11.1:

μ = qr

where

<span> <span>μ⃗ μ→ is the dipole moment vector</span> <span>qiqi is the magnitude of the ithith charge, and</span> <span>r⃗ ir→i is the vector representing the position of ithith charge.</span> </span>

 

r = μ/q

<span>r = [0.838D(3.34×10−30 C⋅m/ 1D)]/ (1.6×10−19 C) *0.124
</span> r = 1.41 x10^-10 m

 

7 0
2 years ago
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The diagram below represents a portion of a cell membrane. The arrow indicates that the cell membrane is carrying out the proces
Llana [10]

Answer:

I'm feeling nice today so heres the answer

Explanation:

In the portion of the cell membrane shown in the diagram, the arrow indicates the process of active transport.

Explanation:

Active transport is one of the mechanisms of transmembrane transport, which involves the use of energy. The diagram (see image) shows the hydrogen (H⁺) output from the cytoplasm to the extracellular space, through an H⁺ pump —consuming ATP— which represents an active transport process.

The hydrophobic nature of the cell membrane prevents the free passage of hydrosoluble elements or ions, as H⁺, so they require the use of active transport to pass through it.

The other options presented are not correct, because

Respiration is a process that occurs in the mitochondria.

Diffusion is a passive transport process that does not require energy.

Cellular recognition depends on membrane proteins that act as specific receptors.

8 0
2 years ago
PART A: Use the following glycolytic reaction to answer the question. If the concentration of DHAP is 0.125 M and the concentrat
d1i1m1o1n [39]

<u>Answer:</u>

<u>For A:</u> The free energy change of the reaction is -5339.76 J/mol

<u>For B:</u> The units of free energy change of the reaction are kJ/mol

<u>For C:</u> The forward reaction is favorable and reverse reaction is unfavorable.

<u>Explanation:</u>

For the given chemical reaction:

DHAP\rightleftharpoons G_3P

  • <u>For A:</u>

Relation between standard Gibbs free energy and equilibrium constant follows:

\Delta G^o=-RT\ln K_{eq}

To calculate the free energy change, we use the equation:

\Delta G=\Delta G^o+RT\ln Q

Or,

\Delta G=-RT^o\ln K_{eq}+RT\ln Q

where,

\Delta G = Free energy change

R = Gas constant = 8.314J/K mol

T^o = standard temperature = 25^oC=[273+25]K=298K

T = temperature of the cell = 37^oC=[273+37]K=310K

K_[eq} = equilibrium constant = 5.4\times 10^{-2}

Q = reaction coefficient = \frac{[G_3P]}{[DHAP]}

[G_3P] = 0.06 M

[DHAP] = 0.125 M

Putting values in above equation, we get:

\Delta G=[-(8.314J/mol.K\times 298K\times \ln (5.4\times 10^{-2}))]+[(8.314J/mol.K\times 310K\times \ln (\frac{0.06}{0.125}))]\\\\\Delta G=-[-7231.46]+[-1891.7]=-5339.76J/mol

Hence, the free energy change of the reaction is -5339.76 J/mol

  • <u>For B:</u>

Converting the free energy change of the reaction into kilojoules, we use the conversion factor:

1 kJ = 1000 J

So, -5339.76J/mol\times \frac{1kJ}{1000J}=-5.34kJ/mol

Hence, the units of free energy change of the reaction are kJ/mol

  • <u>For C:</u>

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative. But, from the above calculation, the Gibbs free energy of the reaction is positive. Thus, the reaction is non-spontaneous.

As, the free energy change of the reaction is negative.

Hence, the forward reaction is favorable and reverse reaction is unfavorable.

8 0
2 years ago
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