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1 year ago

15

A jet ski company charges a flat fee of $24.00 plus $2.25 per hour to rent a jet ski. Another company charges a fee of $23.00 pl

us $2.75 per hour to rent the same jet ski.
Using a graphing calculator, find the number of hours for which the costs are the same. Round your answer to the nearest whole hour.

A) 2
B)10
C)4
D) 8

1 answer:

KatRina [158]1 year ago

5 0

Let the number of hours the ski jet was rented be x, then
For company A, Cost = 2.25x + 24
For company B, Cost = 2.75x + 23

Fro the cost to be the same: 2.25x + 24 = 2.75x + 23
2.75x - 2.25x = 24 - 23
0.5x = 1
x = 1/0.5 = 2
x = 2

The cost are the same after 2 hours.

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Emma's square patio below has been area=31 sq ft. She decides to decrease one dimension by 1 foot and decreases the other dimens

Andreas93 [3]

Answer:

4.57ft by 1.57 ft

Step-by-step explanation:

We are given that

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We have to find the new dimensions of Emma's patio.

Let x be the side of Emma's square patio

We know that

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other dimension= $5.57-4=1.57 ft$

Hence, the new dimension of Emma's patio is given by

4.57ft by 1.57 ft

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2 years ago

The cubit is an ancient unit. Its length equals six palms. (A palm varies from 2.5 to 3.5 inches depending on the individual.) W

olasank [31]

Assuminhg the ark has a shoe-box (cuboid) shape it´s volume would be:

$V_{cuboid}=lenght*width*height$

We have this three measurements ( $l=300cubits;w=50cubits;h=30cubits)$ ) and it can be as simple as replacing them in the equation and solving but they are in all in $cubits$ . We will convert them to $ft$ because the problem requires the answer in $ft^{3}$ . In order to do this we will use the given equivalences:

$1cubit=6palms\\1palm=3.10in$

and another one:

$1ft=12in$

First we will convert from cubits to palms:

$l=300cubits*\frac{6palms}{1cubit}=1800palms\\w=50cubits*\frac{6palms}{1cubit}=300palms\\h=30cubits*\frac{6palms}{1cubit}=180palms\\$

now from $palms$ to $in$ :

$l=1800palms*\frac{3.10in}{1palm}=5580in\\w=300palms*\frac{3.10in}{1palm}=930in\\h=180palms*\frac{3.10in}{1palm}=558in\\$

now from $in$ to $ft$ :

$l=5580in*\frac{1ft}{12in}=465ft\\w=930in*\frac{1ft}{12in}=77.5ft\\h=558in*\frac{1ft}{12in}=46.5ft$

We can calculate the Volume now like this:

$V_{ark}=465ft*77.5ft*46.5ft=1675743.75ft^{3}$

The volume of trhe ark would be $1675743.75ft^{3}$

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1 year ago

You have a net lease for $350 per month. You are responsible for the taxes, which are $6,000 per year. What is your monthly rent

schepotkina [342]

B or C???? I think not really sure

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2 years ago

What’s 8/15 divided by 4/5

iragen [17]

Answer: 2/3

Step-by-step explanation: In this problem, we have 8/15 ÷ 4/5. Dividing by a fraction is the same as multiplying by its reciprocal. In other words, we can change the division sign to multiplication and flip the second fraction.

8/15 ÷ 4/5 can be rewritten as 8/15 × 5/4

Now, we are simply multiplying fractions so we multiply across the numerators and multiply across the denominators.

8/15 × 5/4 = 40/60 = 2/3

8 0

1 year ago

Approximate the area under the curve y = x² from x = 2 to x = 5 using a Right Endpoint approximation with 6 subdivisions.

Tanzania [10]

Answer:

$\text{Area}\,=36.75$

Step-by-step explanation:

Using right estimation point simply means to form a bunch of rectangles between the two limits, x =2 and x = 5. and add the areas of all those rectangles.

There must be 6 subdivisions between 2 and 5. so, to do that:

$\Delta{x}=\dfrac{5-2}{6}=0.5$

the length of each subdivision is 0.5 units. That also means that the 6 rectangles in between the limits will each have the base length of 0.5 units.

So the endpoints of each subdivision from 3 to 5 will be:

$\begin{tabular}{|c|c|c|c|c|}3&3.5&4&4.5&5\\\end{tabular}$

By <em>right </em>endpoint approx<em>, </em>we mean that the height of the rectangles will be determined by the right endpoint of each subdivision, that is, it must be equal to the function value of the first limit.

$\begin{tabular}{|c|c|c|}subdivision&$x$&height($y=x^2$)&3 to 3.5&3.5&12.25&3.5 to 4&4&16&4 to 4.5&4.5&20.25&4.5 to 5&5&25\end$

Note that we have used the right-end-point of the subdivision to determine the height the rectangles.

All that's left to do now is to simply calculate the areas of the each of the rectangles. And add them up.

the base of each of the rectangle is $\Delta{x}=0.5$

and the height is determined in the table above.

$\text{Area}\,=(0.5\times12.25)+(0.5\times16)+(0.5\times20.25)+(0.5\times25)$

$\text{Area}\,=0.5(12.25+16+20.25+25)$

$\text{Area}\,=36.75$

3 0

1 year ago