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2 years ago

If 200 customers buy 45 desserts, how many desserts can you expect to sell to 500 people?

Mathematics

2 answers:

dimaraw [331]2 years ago

6 0

Answer:113

Step-by-step explanation:

You have to add 45 to 45 to get ninety and divide 45 by 2 and get 22.5 and add 22.5 to 90 and get 112.5 and I just rounded it

masha68 [24]2 years ago

5 0

Answer: 112.5 deserts

Step-by-step explanation:

From the question, 200 customers buy 45 desserts. This means that 1 customer will buy 45/200 deserts which will be 0.225 deserts.

To get the desserts that will be sold to 500 people, we multiply the desert sold to one person which is 0.225 multiplied by 500. Mathematically, this will be:

= 0.225 × 500

= 112.5 deserts

This means that 112.5 deserts will be sold to 500 people.

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Sally paid $2.40 for 4 ounces of cinnamon. If there are 16 ounces in 1 pound, how much does cinnamon cost per pound

Marina86 [1]

Answer:

For 1 pound that would $9.20

Step-by-step explanation:

Since there are 16 ounces in 1 pound and Sally paid for 4 with $2.40, what you have to do is take that total and times it by how many you need to times the ounces by to get a pound which would be 4.

4 x 4 = 16

So, that means to get the total for 1 pound you would have to do

$2.40 x 4

Which would equal

$9.20

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2 years ago

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The mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of

grandymaker [24]

Answer:

At the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.

Step-by-step explanation:

We are given that the mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of $2,000.

The ship building association wishes to find out whether their welders earn more or less than $20,000 annually.

Let $\mu$ = mean gross annual incomes of certified welders

So, Null Hypothesis, $H_0$ : $\mu$ = $20,000

Alternate hypothesis, $H_A$ : $\mu \neq$ $20,000

Here, null hypothesis states that the mean income of welders is equal to $20,000.

On the other hand, alternate hypothesis states that the mean income of welders is not $20,000.

Also, the test statistics that would be used here is One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean income

$\sigma$ = population standard deviation = $2,000

n = sample size

Now, at the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.

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2 years ago

The function C(t) below relates outside temperature in degrees Fahrenheit to the number of cricket chirps per minute. It takes a

vekshin1

T is a linear function of C ==> T = mC + b Each additional chirp C corresponds to an increase in T of 0.25 ==> m = 0.25 T = 52 when C = 20 ==> 52 = 0.25(20) + b ==> b = 52 - 5 = 47 So T = 0.25C + 47 When C = 100 then T = 0.25(100) + 47 = 25 + 47 = 72 When C = 120 then T = 0.25(120) + 47 = 30 + 47 = 77 so the temperature range is between 72 and 77 when there are between 100 and 120 chirps per minute

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2 years ago

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The first task of the Segment Two Honors Project is to select the Power Pill study participants’ groups and research board offic

Tatiana [17]

Answer:

Part 1: There are 4.7*10^21 ways to select 40 volunteers in subgroups of 10

Part 2: The research board can be chosen in 32760 ways

Step-by-step explanation:

Part 1:

The number of ways in which we can organized n elements into k groups with size n1, n2,...nk is calculate as:

$\frac{ n!}{ n1!*n2!*...*nk! }$

So, in this case we can form 4 subgroups with 10 participants each one, replacing the values of:

n by 40 participants
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n1, n2, n3 and n4 by 10 participants of every subgroups

We get:

$\frac{ 40!}{10!*10!*10!*10!} = 4.7*10^{21}$

Part 2:

The number of ways in which we can choose k element for a group of n elements and the order in which they are chose matters is calculate with permutation as:

$nPk = \frac{ n!}{(n-k)!}$

So in this case there are 4 offices in the research board, those are director, assistant director, quality control analyst and correspondent. Additionally this 4 offices are going to choose from a group of 5 doctors.

Therefore, replacing values of:

n by 15 doctors
k by 4 offices

We get:

$\frac{ 15!}{ (15-4)! } = 32760$

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2 years ago

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