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lys-0071 [83]
2 years ago
7

A random sample of 81 automobiles traveling on a section of an interstate showed an average speed of 60 mph. The distribution of

speeds of all cars on this section of highway is normally distributed, with a standard deviation of 13.5 mph. Refer to Exhibit A. If we are interested in determining an interval estimate for μ at 86.9% confidence, the z value to use is _____.
a. 1.96
b. 1.31
c. 1.51
d. 2.00
Business
1 answer:
rjkz [21]2 years ago
4 0

Answer:

so correct option is c. 1.51

Explanation:

given data

random sample n = 81

average speed x = 60 mph

standard deviation σ = 13.5 mph

interval estimate  μ =  86.9%

to find out

the value of the z

solution

we have given  μ =  86.9%

so we get here z critical value for the confidence level =  86.9 %

we will use here standard normal table

so z value for 86.9% is 1.51

so correct option is c. 1.51

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A corporate bond with a face value of $1,000 matures in 4 years and has a coupon rate of 6.25 percent. The current price of the
postnew [5]

Answer:

8.28%

Explanation:

We use the Rate formula shown in the spreadsheet for this question

The NPER specifies the time period.  

Given that,  

Present value = $932

Future value or Face value = $1,000  

PMT = 1,000 × 6.25% ÷ 2 = $31.25

NPER = 4 years × 2 = 8 years

The formula is shown below:  

= Rate(NPER;PMT;-PV;FV;type)  

The present value come in negative  

So, after solving this,  

the yield to maturity is 8.28%

6 0
2 years ago
Oriole Company accumulates the following data concerning a mixed cost, using miles as the activity level. Miles Driven Total Cos
Fynjy0 [20]

Answer:

$1.2 per mile

Explanation:

Computation of the variable cost per mile using the high-low method

Using this formula

Variable cost per mile = (Highest activity cost - Lowest activity cost)/(Highest activity - Lowest activity)

Let plug in the

Variable cost per mile= (14,721 - 13,503)/(8,510 - 7,495)

Variable cost per mile= 1,218/1,015

Variable cost per mile=$1.2 per mile

Therefore the Variable cost per mile will be $1.2 per mile.

6 0
2 years ago
(lavilla) lavilla is a village in the italian alps. given its enormous popularity among swiss, german, austrian, and italian ski
bonufazy [111]

The answer is <u>"120 skiers per day".</u>

On average, 1,200 skiers in the village

On average, skiers stay in lavilla for 10 days

how many new skiers are arriving = ?

Applying Little's Law,

Flow Rate = Inventory / Flow Time

= 1200 skiers / 10 days

= 120 skiers per day


4 0
2 years ago
Classifying all data in an organization may be impossible. There has been an explosion in the amount of unstructured data, logs,
Lynna [10]
Por que no se pudo disolver en uno de los recipientes
5 0
2 years ago
On November​ 1, 2018, Arch Services issued $ 337 comma 000 of eight minus year bonds with a stated rate of 15​% at par. Interest
azamat

Answer:

Interest expense to be recorded on Dec 31 2018= $8425

Explanation:

Lets first understand what adjusting entry is? Adjusting entries are entries passed at the reporting date in order to comply to the accruals concept of accounting. Accruals concept requires entities to record revenue and expenses in the period that they occur and should not wait until they are received or paid respectively. Revenues and expenses should be matched for the period and recorded.

Now that we have understood adjusting entry, lets calculate interest expense that should be recorded on December 31 2018. So Arch Services records interest payment on a semi-annul basis (i.e every 6 months). Now the bonds are issued on November (i.e two months to the reporting date), considering the accruals concept Arch Services will have to record interest for two months.

The interest expense is calculated as follows:

Annual Interest= $337000×15%

Annual Interest= $50550

Lets convert it into monthly basis as follows:

Monthly interest expense= $4212.5

Interest for two months would be = $4212.5×2

Interest expense to be recorded on Dec 31 2018= $8425

8 0
1 year ago
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