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VikaD [51]
2 years ago
4

Liquid benzene burns in the atmosphere. If a cold object is placed directly over the benzene, water will condense on the object

and a deposit of soot (carbon) will also form on the object. The chemical equation for this reaction is of the form x1C6H6 + x2O2 → x3C + x4H2O Determine values of x1, x2, x3, and x4 to balance the equation
Chemistry
1 answer:
Liono4ka [1.6K]2 years ago
4 0

<u>Answer:</u> The value of x_1,x_2,x3\text{ and }x_4 are 2, 3, 12 and 6 respectively.

<u>Explanation:</u>

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.  

A balanced chemical equation always follow this law.

For the given chemical reaction, the balanced equation follows:

2C_6H_6+3O_2\rightarrow 12C+6H_2O

By Stoichiometry of the reaction:

2 moles of benzene reacts with 3 mole of oxygen gas to produce 12 moles of carbon and 6 moles of water

From the above reaction:

x_1=2\\x_2=3\\x_3=12\\x_4=6

Hence, the value of x_1,x_2,x3\text{ and }x_4 are 2, 3, 12 and 6 respectively.

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Which of the following mixtures, with each component present at a concentration of 0.1 M, has a pH closest to 7? O A. HCIO(aq) a
eduard

for HClO, pKa = 7.54

for HNO_2, pKa = 3.15                                    

for CH3 COOH, pKa = 4.74    

Explanation:

The concentration of the solution given is 0.1 M has a pH closest to 7

The mixtures are weak acids and their salts except

HNO_3 and NaNO_3                                         pH = pH is near to '1'

for buffers( acidic)                                               pH = pKa + log [salt] / [acid]

therefore [salt] = [acid] = 0.1                               pH = pKa + log 0.1 / 0.1 = pKa

                                                     pH = pKa

for HClO, pKa = 7.54

for HNO_2, pKa = 3.15                                     therefore HClO and NaclO

                                                                         mixture hs a pH closest to '7'

for CH3 COOH, pKa = 4.74                

5 0
2 years ago
Read 2 more answers
SnO2 is reduced by carbon according to this reaction: SnO2 + C ???? Sn + CO2. How many liters of CO2 are produced if 300.0 grams
andrew-mc [135]

Explanation:

The given reaction is as follows.

         SnO_{2} + C \rightarrow Sn + O_{2}

a).   Molar mass of SnO_{2} is [(mass of Sn) + (2 × mass of O)].

Therefore, molar mass of SnO_{2} = (118.7 + 2 × 16) g/mol = 150.7 g/mol

Since, it is known that number of moles equal mass divided by molar mass. So, moles of Sn will be calculated as follows.

               No. of moles = \frac{mass}{molar mass of SnO_{2}}

                                      = \frac{300 g}{150.7 g/mol}

                                      = 2.53 mol

As it is given that 1 mole of SnO_{2} produces 1 moles of Sn and 1 moles of CO_{2}. Hence, 2.53 moles of SnO_{2} will also produce 2.53 moles of Sn and 2.53 moles of CO_{2}.

Volume of 1 mole of CO_{2} at STP is 22.4 L. Therefore, volume of 2.53 moles of CO_{2} will be calculated as follows.

                  2.53 × 22.5 L = 56.67 L

Hence, 56.67 L of CO_{2} are produced if 300.0 grams of tin are produced at STP.

b).  Mass of tin is given as 1800.0 g. So, number of moles will be calculated as follows.

               No. of moles = \frac{mass}{molar mass of tin}

                                      = \frac{1800.0 g}{118.7 g/mol}

                                      = 15.2 moles

As 15.2 moles of SnO_{2} produces 15.2 moles of Sn. Therefore, weight of SnO_{2} will be calculated as follows.

                   Mass = no. of moles × molar mass of SnO_{2}

                             = 15.2 moles × 150.7 g/mol

                             = 2290.64 g

Hence, 2290.64 grams of SnO_{2} are required to produce 1800.0 grams of tin.

c).   Mass of carbon given is 100.0 grams.

             No. of moles = \frac{mass}{molar mass of carbon}

                                    = \frac{100 g}{12 g/mol}

                                      = 8.33 moles

As, 1 mole of carbon is produced by 1 mole of tin. So, 8.33 mole of carbon will be produced by 8.33 moles of tin.

Therefore, calculate mass of tin produced as follows.

                        Mass = no. of moles × molar mass of Sn

                             = 8.33 moles × 118.7 g/mol

                             = 988.8 g

Hence, 988.8 grams of tin will be produced per 100 grams of carbon used.

8 0
2 years ago
What mass of titanium is produced from 380g of titanium chloride?
emmainna [20.7K]
Molar mass of TiCl₃ = (47.9 + 35.5×3) g/mol = 154.4 g/mol 
No. of moles of TiCl₃ = (380 g) / (154.4 g/mol) = 2.46 mol 

1 mole of TiCl₃ contains 1 mole of Ti. 
No. of moles of Ti needed = (2.46 mol) × 1 = 2.46 mol 

Molar mass of Ti = 47.9 g/mol 
Mass of Ti needed = (2.46 mol) × (47.9 g/mol) = 118 g
7 0
2 years ago
Which of the following chemical equations does not correspond to a standard molar enthalpy of formation? a. Mg(s) + C(s) + 3/2 O
goblinko [34]

Answer:

N₂_{s}  + O₂_{g}   →  2NO_{g}

Explanation:

  The given equations are:

      Mg_{s} + C_{s} + \frac{3}{2}O_{g}   →     MgCO₃_{s}

   

      C_{s} +  \frac{1}{2}O₂_{g}    →   CO_{g}

      N₂_{s}  + O₂_{g}   →  2NO_{g}

     

      N₂_{s}  + 2O₂_{g}    →  N₂O_{g}

      H₂_{g} + \frac{1}{2}O_{g}    →    HO_{l}

From the given equations only N₂_{s}  + O₂_{g}   →  2NO_{g} does not correspond to an expression of the standard molar enthalpy of formation.

  • The heat of formation is the heat liberated or absorbed when one mole of a compound is formed from its constituent elements under standard conditions.

 The equation must result in the formation of only one mole of the compound.

It could have been properly written as

   \frac{1}{2}N₂_{s}  +  \frac{1}{2}O₂_{g}   →  NO_{g}

5 0
2 years ago
What is the [H3O+]in a solution of pOH 0.253
Luda [366]
Carbonated water would be what you are looking for :v)
4 0
2 years ago
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