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3241004551 [841]
2 years ago
9

A 2.0-kg projectile moves from its initial position to a point that is displaced 20 m horizontally and 15 m above its initial po

sition. How much work is done by the gravitational force on the projectile
Physics
2 answers:
user100 [1]2 years ago
8 0

Answer:

W= - 300 J

Explanation:

Given that

Mass ,m= 2 kg

Horizontal distance ,x= 20 m

Vertical distance ,y= 15 m

As we know that gravity force always acts in the downward direction

F= m g

The displacement of the object is in upward direction

d= -15 m

The work done by a force given as

W= F.d

Now by putting the values

W= - 2 x 10 x 15                ( Take g= 10 m/s²)

W= - 20 x 15

W= - 300 J

Therefore the work done by gravitational force will be -300 J.

Maurinko [17]2 years ago
7 0

Answer:

W = 294 J

Explanation:

given,

mass of the projectile = 2 Kg

horizontal displacement = 20 m

vertical displacement = 15 m

work done by the gravitational force = ?

the work done by gravitational force only account for vertical motion.

force due to gravity =  m g

                                 = 2 x 9.8 = 19.6 N

work done is equal force x displacement

W = F x s

W = 19.6 x 15

W = 294 J

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A mover hoists a 50 kg box from the ground to a height of 2 m. What was the change in the box's energy
SSSSS [86.1K]

Answer:

980 J

Explanation:

The change in box's energy is equal to its change in gravitational potential energy:

\Delta U = m g \Delta h

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m = 50 kg is the mass of the box

g = 9.8 m/s^2 is the acceleration due to gravity

\Delta h= 2m is the change in height of the box

Substituting numbers, we find

\Delta U = (50 kg)(9.8 m/s^2)(2 m)=980 J

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Water is kept in a vessel at a temperature of 100°C. What would happen if a metal ball having a temperature of 30°C is dropped i
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If a 110 kg go-cart traveling at a velocity of 13.41 m/s has a collision with an impulse of 615 Nxs, what is the
mafiozo [28]

Answer:

5.59 m/s

Explanation:

We are given;

Mass = 110 kg

Initial velocity: u = 13.41 m/s

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Thus;

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2 years ago
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