Answer:
Maximum height the atmosphere pressure can support the
water=10.336 m
Explanation:
We know that ,

Case 1 - Mercury in the tube

Case 2 - Water in the tube

Since atmospheric pressure is same
.
or, 

∴ 
Hence height of the water column =10.336 m
<em>To determine the y component of velocity of a projectile </em><u><em>sine </em></u><em>operation is performed on the angle of launch.</em>
<u>Answer:</u> <em>sine</em>
<u>Explanation:</u>
Thus 
The initial velocity u can be resolved along two directions.
Along the X direction initial velocity = u cos θ
Along y direction initial velocity= u sin θ
From the equation of motion 
Thus velocity along x direction
=u cos θ
Velocity along y direction
= u sinθ -gt
Sign of g is negative.
A. The friction between two pieces of sandpaper is greater than
the friction between any of the pairs of surfaces.
D. Juan should decrease the mass of his go-kart. Then any force
that pushes it forward will give it greater forward acceleration.
Answer:
How much energy does it take to melt a 16.87 g ice cube? ΔHfus = 6.02 kJ/mol How much energy does it take to melt a 16.87 g ice cube? = 6.02 kJ/mol
A. 108 kJ
B. 102 kJ
C. 5.64 kJ
D. 936 kJ
E. none of the above
<em>5.64 kJ</em>
Explanation:
The Heat of fusion is the heat energy required to dissolve a given mass of ice at melting point.
<h3>
Step by Step Calculation</h3>
The heat energy required to dissolve ice can be calculated using the expression below;
Q = ΔH
x m ...............................................1
where Q is the heat energy required;
ΔH
is the heat of fusion for ice;
m is the mole
All the parameters above are provided in the question except m, so to get m we use the molar mass of water (also for ice) which is 18.01528 g/mol
.
<em>This means that 18.01528 g of ice is contained in one mole, therefore the mole for 16.87 g of ice is given as;</em>

m = 0.9364 mole of ices
Now the parameters are complete, we are given;
ΔH
= 6.02 kJ/mol
m = 0.9364 mol
Q =?
Substituting into equation 1, we have
Q = 6.02 kJ/mol x 0.9364 mol
Q = 5.64 kJ
<em>Therefore, the energy required to melt 16.87 g of ice is 5.64 kJ</em>
vf=vi+at
No need for rearranging because it is already set up for Vf (final velocity)
a= -9.8m/s² (because it is falling)
vi= 0
t= 2.7
0 + -9.8(2.7) = vf
vf = -26.5 (-26.46)