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dlinn [17]
2 years ago
7

How does the sun's energy help maintain Earth's energy budget? A part of it is trapped by carbon dioxide and methane. A part of

it heats up Earth's land and water equally. All of it is turned back towards space. All of it is trapped by the clouds.
Physics
2 answers:
Andru [333]2 years ago
7 0

Answer:

Hi! Hope your having a great day so far!

Your answer is gonna be B, part of it heats up Earth's land and water equally.

The sun's energy help maintains Earth's energy budgets as the sunlight energy being absorbed by land and water from the sun. This results in the release on energy in the form of water vapors, gases like nitrogen dioxide, carbon dioxide, methane are again radiate back to the atmosphere. The water vapor chiefly is responsible for causing rain which is necessary for maintaining the life on earth. The other gases maintains the global temperatures.

I hope this helped!

Have a fantastical day!!!

(Also it would make my day if you marked me as brainliest!)

~Lola

Grace [21]2 years ago
5 0

Answer: A part of it heats up Earth's land and water equally.

The sun's energy help maintains Earth's energy budgets as the sunlight energy being absorbed by land and water from the sun. This results in the release on energy in the form of water vapors, gases like nitrogen dioxide, carbon dioxide, methane are again radiate back to the atmosphere. The water vapor chiefly is responsible for causing rain which is necessary for maintaining the life on earth. The other gases maintains the global temperatures.

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Answer:

A) 0.957 J

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A capacitor with plates separated by distance d is charged to a potential difference ΔVC. All wires and batteries are disconnect
fgiga [73]

Answer:

Yes, the capacitor's Q load varies inversely proportional to the distance between plates.

Explanation:

In the attached files you see the inverse relationship between capacity and distance between plates "d".

In the following formula we see its relationship with the "Q" load

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Springfield's "classic rock" radio station broadcasts at a frequency of 102.1 mhz. what is the length of the radio wave in meter
Mila [183]
The frequency of the radio wave is:
f=102.1 MHz = 102.1 \cdot 10^6 Hz

The wavelength of an electromagnetic wave is related to its frequency by the relationship
\lambda= \frac{c}{f}
where c is the speed of light and f the frequency. Plugging numbers into the equation, we find
\lambda= \frac{3 \cdot 10^8 m/s}{102.1 \cdot 10^6 Hz}= 2.94 m
and this is the wavelength of the radio waves in the problem.
7 0
2 years ago
In at least 150 words, discuss how Chang's use of personification, metaphor, or connotation express one his themes in "Garden of
Kay [80]
<span>Poet Kuangchi Chang did not remain in China long enough to be "re-educated." Following the Communist takeover he fled to the United States. His poem "Garden of My Childhood" describes China before the revolution as a peaceful, idyllic garden with a violent horde rapidly approaching. A vine, the wind, and the sea are each personified, and each beckons for him to run. It is not until "eons later," when he is "worlds away," that his "running is all done," and he finds himself at his destination: another garden, just like the one he had left behind.</span>
6 0
2 years ago
Evaporation of sweat requires energy and thus take excess heat away from the body. Some of the water that you drink may eventual
kotegsom [21]

Answer:

The amount of heat required is H_t =  1.37 *10^{6} \ J

Explanation:

From the question we are told that

The mass of water is m_w  =  20 \ ounce = 20 * 28.3495 = 5.7 *10^2 g

The temperature of the water before drinking is T_w  =  3.8 ^oC

The temperature of the body is T_b  =  36.6^oC

Generally the amount of heat required to move the water from its former temperature to the body temperature is

H=  m_w  *  c_w * \Delta T

Here c_w is the specific heat of water with value c_w = 4.18 J/g^oC

So

H=   5.7 *10^2 * 4.18 * (36.6 - 3.8)

=> H= 7.8 *10^{4} \  J

Generally the no of mole of sweat present mass of water is

n = \frac{m_w}{Z_s}

Here Z_w is the molar mass of sweat with value

Z_w =  18.015 g/mol

=> n = \frac{5.7 *10^2}{18.015}

=> n = 31.6 \  moles

Generally the heat required to vaporize the number of moles of the sweat is mathematically represented as

H_v  =  n  *  L_v

Here L_v is the latent heat of vaporization with value L_v  = 7 *10^{3} J/mol

=> H_v  =  31.6 * 7 *10^{3}

=> H_v  = 1.29 *10^{6} \  J

Generally the overall amount of heat energy required is

H_t =  H +  H_v

=> H_t =  7.8 *10^{4} +  1.29 *10^{6}

=> H_t =  1.37 *10^{6} \ J

4 0
2 years ago
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